题目内容
某汽车租赁公司要购买轿车和面包车共10辆,其中轿车至少要购3辆.轿车每辆7万元,面包车每辆4万元.公司投入购车的资金不超过58万元,设购买轿车为x辆,所需资金为所需资金为y万元.
(1)写出y与x的函数关系式;
(2)求出自变量x的取值范围;
(3)若公司投入资金为52万元,问轿车和面包车各购多少辆?
(1)写出y与x的函数关系式;
(2)求出自变量x的取值范围;
(3)若公司投入资金为52万元,问轿车和面包车各购多少辆?
.解:(1)
即
(2)∵
∴
∴
且
∴自变量x的取值范围是
且x为正整数. (3)∵
∴
∴
∴
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且
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
∴

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略
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