题目内容
因式分解:
(1)-x3+2x2y-xy2
(2)x2(x-2)+4(2-x)
(1)-x3+2x2y-xy2
(2)x2(x-2)+4(2-x)
(1)原式=-x(x2-2xy+y2)=-x(x-y)2;
(2)原式=x2(x-2)-4(x-2)=(x-2)(x2-4)=(x-2)(x-2)(x+2)=(x-2)2(x+2).
(2)原式=x2(x-2)-4(x-2)=(x-2)(x2-4)=(x-2)(x-2)(x+2)=(x-2)2(x+2).
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