题目内容
已知0<a<1,化简a+
|
a+
|
分析:因为a=(
)2,
=
,又0<a<1,所以(
)2<
,即
<
.
a |
1 |
a |
1 | ||
(
|
a |
1 | ||
(
|
a |
1 | ||
|
解答:解:∵0<a<1,
∴
<
,
∴原式=
-
=
-
=
+
-(
-
)=2
.
∴
a |
1 | ||
|
∴原式=
(
|
(
|
=
(
|
(
|
=
a |
1 | ||
|
1 | ||
|
a |
a |
点评:注意当x<0时,
=-x.
x2 |
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