题目内容
计算:
(1)(ab2)2•(-a3b)3÷(-5ab)
(2)[(x+y)2-(x-y)2]÷(2xy)
(1)(ab2)2•(-a3b)3÷(-5ab)
(2)[(x+y)2-(x-y)2]÷(2xy)
(1)原式=a2b4•(-a9b3)÷(-5ab)
=
a10b6.
(2)原式=[x2+2xy+y2-x2+2xy-y2]÷2xy
=4xy÷2xy
=2.
=
1 |
5 |
(2)原式=[x2+2xy+y2-x2+2xy-y2]÷2xy
=4xy÷2xy
=2.
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