题目内容
![](http://thumb.1010pic.com/pic3/upload/images/201304/20/8b063f7b.png)
2
5 |
2
.5 |
分析:连接OA,求出OP,OA,根据勾股定理求出AP,根据垂径定理得出AB=2AP即可.
解答:解:连接OA,![](http://thumb.1010pic.com/pic3/upload/images/201304/23/4d2e91fd.png)
∵CD=6,PD=1,CD是⊙O的直径,
∴OA=OC=3,OP=3-2=2,
由勾股定理得:AP=
=
,
∵直径CD⊥AB,
∴AB=2AP=2
,
故答案为:2
![](http://thumb.1010pic.com/pic3/upload/images/201304/23/4d2e91fd.png)
∵CD=6,PD=1,CD是⊙O的直径,
∴OA=OC=3,OP=3-2=2,
由勾股定理得:AP=
32-22 |
5 |
∵直径CD⊥AB,
∴AB=2AP=2
5 |
故答案为:2
5 |
点评:本题考查了勾股定理和垂径定理的应用.
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