题目内容
如图,四边形ABCD中,AB = AD,∠BAD=90°,∠CBD=30°,∠BCD=45°,
若AB=
.求四边形
的面积.
若AB=




试题分析:解:过D做DM⊥BC于点M。

已知AB=AD。Rt△ABD和Rt△CDM为等腰直角三角形。
Rt△ABD中BD=

BM=

所以Rt△CDM中,CM=DM=2.所以S△BCD=

S△ABD=

则四边形ABCD面积=

点评:本题难度中等,主要考查学生对几何图形面积求解和勾股定理知识点的掌握。

练习册系列答案
相关题目