题目内容
| 1 |
| 1×2 |
| 1 |
| 2×3 |
| 1 |
| 3×4 |
| 1 |
| 4×5 |
| 1 |
| 5×6 |
考点:分数的拆项
专题:计算问题(巧算速算)
分析:把每一项中的分数拆分为两个分数的差的形式,然后通过加减相互抵消,达到简算的目的.
解答:
解:
+
+
+
+
=1-
+
-
+
-
+
-
+
-
=1-
=
| 1 |
| 1×2 |
| 1 |
| 2×3 |
| 1 |
| 3×4 |
| 1 |
| 4×5 |
| 1 |
| 5×6 |
=1-
| 1 |
| 2 |
| 1 |
| 2 |
| 1 |
| 3 |
| 1 |
| 3 |
| 1 |
| 4 |
| 1 |
| 4 |
| 1 |
| 5 |
| 1 |
| 5 |
| 1 |
| 6 |
=1-
| 1 |
| 6 |
=
| 5 |
| 6 |
点评:本题考查了利用分数的拆项进行简算,知识点:
=
-
| 1 |
| n(n-1) |
| 1 |
| n-1 |
| 1 |
| n |
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