题目内容
(2012?安徽模拟)怎样算简便就怎样算
4÷
-
÷4-4
×2003+2005×25%+2004×0.75
[1-(
+
)]×24
÷[(
+
)×
].
4÷
| 4 |
| 5 |
| 4 |
| 5 |
| 4 |
| 5 |
| 1 |
| 4 |
[1-(
| 1 |
| 3 |
| 1 |
| 4 |
| 1 |
| 3 |
| 2 |
| 3 |
| 1 |
| 5 |
| 1 |
| 13 |
分析:(1)按照分数的四则混合运算进行计算即可;
(2)将
转化成小数是0.25,25%转化成小数是0.25,再将0.75改写成0.25乘以3的形式,然后利用乘法分配律进行计算即可;
(3)可将算式中的小括号去掉,然后利用乘法分配律进行计算;
(4)根据分数的四则混合运算进行计算即可.
(2)将
| 1 |
| 4 |
(3)可将算式中的小括号去掉,然后利用乘法分配律进行计算;
(4)根据分数的四则混合运算进行计算即可.
解答:解:(1)4÷
-
÷4-4
=5-
-4
,
=4
-4
,
=0;
(2)
×2003+2005×25%+2004×0.75,
=0.25×2003+2005×0.25+2004×0.25×3,
=0.25×(2003+2005+2004×3),
=0.25×(2003+2005+6012),
=0.25×10020,
=2505;
(3)[1-(
+
)]×24
=[1-
-
]×24,
=1×24-
×24-
×24,
=24-8-6,
=10;
(4)
÷[(
+
)×
]
=
÷[
×
],
=
÷
,
=5.
| 4 |
| 5 |
| 4 |
| 5 |
| 4 |
| 5 |
=5-
| 1 |
| 5 |
| 4 |
| 5 |
=4
| 4 |
| 5 |
| 4 |
| 5 |
=0;
(2)
| 1 |
| 4 |
=0.25×2003+2005×0.25+2004×0.25×3,
=0.25×(2003+2005+2004×3),
=0.25×(2003+2005+6012),
=0.25×10020,
=2505;
(3)[1-(
| 1 |
| 3 |
| 1 |
| 4 |
=[1-
| 1 |
| 3 |
| 1 |
| 4 |
=1×24-
| 1 |
| 3 |
| 1 |
| 4 |
=24-8-6,
=10;
(4)
| 1 |
| 3 |
| 2 |
| 3 |
| 1 |
| 5 |
| 1 |
| 13 |
=
| 1 |
| 3 |
| 13 |
| 15 |
| 1 |
| 13 |
=
| 1 |
| 3 |
| 1 |
| 15 |
=5.
点评:此题主要考查的是分数、小数的四则混合运算和简便运算.
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