题目内容
解方程.
X×
=
4X÷
=45
X+
=
50%X=4.
X×
| 5 |
| 7 |
| 5 |
| 14 |
| 2 |
| 9 |
| 1 |
| 2 |
| 1 |
| 6 |
| 3 |
| 8 |
分析:(1)根据等式的性质,两边同除以
即可;
(2)根据等式的性质,两边同乘
,再同除以4即可;
(3)根据等式的性质,两边同减去
,再同乘2即可;
(4)把50%化成小数为0.5,原式变成0.5x=4,再根据等式的性质,两边同除以0.5即可.
| 5 |
| 7 |
(2)根据等式的性质,两边同乘
| 2 |
| 9 |
(3)根据等式的性质,两边同减去
| 1 |
| 6 |
(4)把50%化成小数为0.5,原式变成0.5x=4,再根据等式的性质,两边同除以0.5即可.
解答:解:(1)X×
=
,
X×
÷
=
÷
,
X=
×
,
X=
;
(2)4X÷
=45,
4X÷
×
=45×
,
4X=10,
4X÷4=10÷4,
X=2.5;
(3)
X+
=
,
X+
-
=
-
,
X=
,
X×2=
×2,
X=
;
(4)50%X=4,
0.5x=4,
0.5x÷0.5=4÷0.5,
x=8.
| 5 |
| 7 |
| 5 |
| 14 |
X×
| 5 |
| 7 |
| 5 |
| 7 |
| 5 |
| 14 |
| 5 |
| 7 |
X=
| 5 |
| 14 |
| 7 |
| 5 |
X=
| 1 |
| 2 |
(2)4X÷
| 2 |
| 9 |
4X÷
| 2 |
| 9 |
| 2 |
| 9 |
| 2 |
| 9 |
4X=10,
4X÷4=10÷4,
X=2.5;
(3)
| 1 |
| 2 |
| 1 |
| 6 |
| 3 |
| 8 |
| 1 |
| 2 |
| 1 |
| 6 |
| 1 |
| 6 |
| 3 |
| 8 |
| 1 |
| 6 |
| 1 |
| 2 |
| 5 |
| 24 |
| 1 |
| 2 |
| 5 |
| 24 |
X=
| 5 |
| 12 |
(4)50%X=4,
0.5x=4,
0.5x÷0.5=4÷0.5,
x=8.
点评:此题考查了根据等式的性质解方程,即方程两边同加、同减、同乘或同除以某数(0除外),方程的左右两边仍相等;注意“=”号上下要对齐.
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