题目内容
合理灵活地进行计算.
|
|
4×[(
| ||||||||||||||||
|
( 6-
|
分析:(1)利用连续除以两个数,等于除以这两个数的积进行计算;
(2)利用乘法的分配律进行计算;
(3)(5)根据分数四则混合运算的顺序,先算乘除后算加减,有括号的先算括号里面的;
(4)先利用除以一个数等于乘以这个数的倒数,然后利用乘法的分配律;
(2)利用乘法的分配律进行计算;
(3)(5)根据分数四则混合运算的顺序,先算乘除后算加减,有括号的先算括号里面的;
(4)先利用除以一个数等于乘以这个数的倒数,然后利用乘法的分配律;
解答:解:(1)
÷
÷
,
=
÷(
×
),
=
÷
,
=1
,
(2)
×(
-
),
=
×
-
×
,
=
-
,
=
,
(3)4×[(
+
)÷6],
=4×(
÷6),
=4×
,
=1,
(4)
×
+
÷15,
=
×
+
×
,
=(
+
)×
,
=1×
,
=
,
(5)(6-
×32 )+
,
=(6-4)+
,
=2+
,
=2
.
| 5 |
| 8 |
| 20 |
| 21 |
| 7 |
| 12 |
=
| 5 |
| 8 |
| 20 |
| 21 |
| 7 |
| 12 |
=
| 5 |
| 8 |
| 5 |
| 9 |
=1
| 1 |
| 8 |
(2)
| 3 |
| 4 |
| 17 |
| 18 |
| 5 |
| 9 |
=
| 3 |
| 4 |
| 17 |
| 18 |
| 3 |
| 4 |
| 5 |
| 9 |
=
| 17 |
| 24 |
| 5 |
| 12 |
=
| 7 |
| 24 |
(3)4×[(
| 5 |
| 6 |
| 2 |
| 3 |
=4×(
| 3 |
| 2 |
=4×
| 1 |
| 4 |
=1,
(4)
| 3 |
| 7 |
| 1 |
| 15 |
| 4 |
| 7 |
=
| 3 |
| 7 |
| 1 |
| 15 |
| 4 |
| 7 |
| 1 |
| 15 |
=(
| 3 |
| 7 |
| 4 |
| 7 |
| 1 |
| 15 |
=1×
| 1 |
| 15 |
=
| 1 |
| 15 |
(5)(6-
| 1 |
| 8 |
| 3 |
| 4 |
=(6-4)+
| 3 |
| 4 |
=2+
| 3 |
| 4 |
=2
| 3 |
| 4 |
点评:此题考查了分数的四则混合运算,在能利用简便方法的时候要利用简算,比如:乘法的分配律,除法的简算等.
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