题目内容
计算下列各式.
(1)(3
-4×
×0.25-
)÷
(2)
×13+
×24+51
×
(3)(3
+4
)×2.5+(6.875+5
)×2
(4)
-
+
-
+
)-3
]÷
.
(1)(3
| 1 |
| 3 |
| 2 |
| 3 |
| 1 |
| 3 |
| 5 |
| 3 |
(2)
| 7 |
| 31 |
| 13 |
| 31 |
| 4 |
| 5 |
| 5 |
| 7 |
(3)(3
| 1 |
| 8 |
| 5 |
| 7 |
| 2 |
| 7 |
| 1 |
| 2 |
(4)
| 49 |
| 12 |
| 63 |
| 20 |
| 77 |
| 30 |
| 91 |
| 42 |
| 105 |
| 56 |
| 1 |
| 6 |
| 1 |
| 24 |
分析:(1)先把小括号里面的乘法运用乘法结合律简算,再运用减法的性质简算,最后算括号外的除法;
(2)先运用乘法分配律简算,再算最后一个乘法,最后算加法;
(3)先算小括号里面的加法,再算括号外的乘法;
(4)先提取7,变成7×(
-
+
-
+
),再根据
=
-
,
=
+
…进行化简,进而求解.
(2)先运用乘法分配律简算,再算最后一个乘法,最后算加法;
(3)先算小括号里面的加法,再算括号外的乘法;
(4)先提取7,变成7×(
| 7 |
| 12 |
| 9 |
| 20 |
| 11 |
| 30 |
| 13 |
| 42 |
| 15 |
| 56 |
| 7 |
| 12 |
| 1 |
| 3 |
| 1 |
| 4 |
| 9 |
| 20 |
| 1 |
| 4 |
| 1 |
| 5 |
解答:解:(1)(3
-4×
×0.25-
)÷
,
=(3
-4×0.25×
-
)÷
,
=(3
-
-
)÷
,
=(3
-
-
)÷
,
=(3-
)÷
,
=
×
,
=
;
(2)
×13+
×24+51
×
,
=
×7+
×24+51
×
,
=
×(7+24)+51
×
,
=
×31+51
×
,
=13+37,
=50;
(3)(3
+4
)×2
,
=
×
,
=
;
(4)
-
+
-
+
,
=7×(
-
+
-
+
),
=7×(
+
-
-
+
+
-
-
+
+
),
=7×(
+
),
=7×
,
=
.
| 1 |
| 3 |
| 2 |
| 3 |
| 1 |
| 3 |
| 5 |
| 3 |
=(3
| 1 |
| 3 |
| 2 |
| 3 |
| 1 |
| 3 |
| 5 |
| 3 |
=(3
| 1 |
| 3 |
| 2 |
| 3 |
| 1 |
| 3 |
| 5 |
| 3 |
=(3
| 1 |
| 3 |
| 1 |
| 3 |
| 2 |
| 3 |
| 5 |
| 3 |
=(3-
| 2 |
| 3 |
| 5 |
| 3 |
=
| 7 |
| 3 |
| 3 |
| 5 |
=
| 7 |
| 5 |
(2)
| 7 |
| 31 |
| 13 |
| 31 |
| 4 |
| 5 |
| 5 |
| 7 |
=
| 13 |
| 31 |
| 13 |
| 31 |
| 4 |
| 5 |
| 5 |
| 7 |
=
| 13 |
| 31 |
| 4 |
| 5 |
| 5 |
| 7 |
=
| 13 |
| 31 |
| 4 |
| 5 |
| 5 |
| 7 |
=13+37,
=50;
(3)(3
| 1 |
| 8 |
| 5 |
| 7 |
| 1 |
| 2 |
=
| 439 |
| 56 |
| 5 |
| 2 |
=
| 2195 |
| 112 |
(4)
| 49 |
| 12 |
| 63 |
| 20 |
| 77 |
| 30 |
| 91 |
| 42 |
| 105 |
| 56 |
=7×(
| 7 |
| 12 |
| 9 |
| 20 |
| 11 |
| 30 |
| 13 |
| 42 |
| 15 |
| 56 |
=7×(
| 1 |
| 3 |
| 1 |
| 4 |
| 1 |
| 4 |
| 1 |
| 5 |
| 1 |
| 5 |
| 1 |
| 6 |
| 1 |
| 6 |
| 1 |
| 7 |
| 1 |
| 7 |
| 1 |
| 8 |
=7×(
| 1 |
| 3 |
| 1 |
| 8 |
=7×
| 11 |
| 24 |
=
| 77 |
| 24 |
点评:本题考查了四则混合运算,注意运算顺序和运算法则,灵活运用所学的运算定律进行简便计算.
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