题目内容
计算.
×
-
÷
+
×1
49
÷7+1.5÷(0.5-
)
×5
+4
×0.75
(6
×5.43+4.57÷
)-(1
+
)×1.44.
| 6 |
| 5 |
| 2 |
| 3 |
| 2 |
| 7 |
| 4 |
| 7 |
| 2 |
| 3 |
| 4 |
| 5 |
49
| 7 |
| 8 |
| 1 |
| 3 |
| 3 |
| 4 |
| 1 |
| 6 |
| 5 |
| 6 |
(6
| 1 |
| 4 |
| 4 |
| 25 |
| 11 |
| 24 |
| 5 |
| 6 |
分析:(1)把除法改为乘法,运用加法交换律与结合律简算;
(2)把49
拆成整数与分数相加的形式,运用除法的性质简算,1.5÷(0.5-
)按运算顺序计算;
(3)把
改为小数,运用乘法分配律的逆运算简算;
(4)第一个括号把除法改为乘法,运用乘法分配律的逆运算简算,(1
+
)×1.44,运用乘法分配律简算.
(2)把49
| 7 |
| 8 |
| 1 |
| 3 |
(3)把
| 3 |
| 4 |
(4)第一个括号把除法改为乘法,运用乘法分配律的逆运算简算,(1
| 11 |
| 24 |
| 5 |
| 6 |
解答:解:(1)
×
-
÷
+
×1
,
=(
+1
)×
-
×
,
=3×
-
,
=2-
,
=1
;
(2)49
÷7+1.5÷(0.5-
),
=(49+
)÷7+1.5÷(
-
),
=49÷7+
÷7+1.5÷
,
=7+
×
+1.5×6,
=7+
+9,
=16
;
(3)
×5
+4
×0.75,
=0.75×5
+4
×0.75,
=(5
+4
)×0.75,
=10×0.75,
=7.5;
(4)(6
×5.43+4.57÷
)-(1
+
)×1.44,
=(
×5.43+4.57×
)-(
×1.44+
×1.44),
=(5.43+4.57)×
-(2.1+1.2),
=10×
-3.3,
=62.5-3.3,
=59.2.
| 6 |
| 5 |
| 2 |
| 3 |
| 2 |
| 7 |
| 4 |
| 7 |
| 2 |
| 3 |
| 4 |
| 5 |
=(
| 6 |
| 5 |
| 4 |
| 5 |
| 2 |
| 3 |
| 2 |
| 7 |
| 7 |
| 4 |
=3×
| 2 |
| 3 |
| 1 |
| 2 |
=2-
| 1 |
| 2 |
=1
| 1 |
| 2 |
(2)49
| 7 |
| 8 |
| 1 |
| 3 |
=(49+
| 7 |
| 8 |
| 1 |
| 2 |
| 1 |
| 3 |
=49÷7+
| 7 |
| 8 |
| 1 |
| 6 |
=7+
| 7 |
| 8 |
| 1 |
| 7 |
=7+
| 1 |
| 8 |
=16
| 1 |
| 8 |
(3)
| 3 |
| 4 |
| 1 |
| 6 |
| 5 |
| 6 |
=0.75×5
| 1 |
| 6 |
| 5 |
| 6 |
=(5
| 1 |
| 6 |
| 5 |
| 6 |
=10×0.75,
=7.5;
(4)(6
| 1 |
| 4 |
| 4 |
| 25 |
| 11 |
| 24 |
| 5 |
| 6 |
=(
| 25 |
| 4 |
| 25 |
| 4 |
| 35 |
| 24 |
| 5 |
| 6 |
=(5.43+4.57)×
| 25 |
| 4 |
=10×
| 25 |
| 4 |
=62.5-3.3,
=59.2.
点评:分数四则混合运算的解题方法不是一成不变的,要根据题目的具体情况,如数的特征、运算符号等决定做题方法.
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