题目内容
我会巧算下列各题.
736+302
682-298
901+902+905+898-907+908-895
99999+9999+999+99+9+4.
736+302
682-298
901+902+905+898-907+908-895
99999+9999+999+99+9+4.
分析:(1)把302化成300+2进行简算;
(2)把298看作300-2,再运用减法的性质进行简算;
(3)原式=900+1+900+2+900+5+900-2-900-7+900+8-900+5=900×5-(1+2+5-2-7+8+5);
(4)把4化成1+1+1+1,原式=99999+9999+999+99+9+5-1=99999+9999+999+99+9+1+1+1+1+1-1=(99999+1)+(9999+1)+(999+1)+(99+1)+(9+1)-1.
(2)把298看作300-2,再运用减法的性质进行简算;
(3)原式=900+1+900+2+900+5+900-2-900-7+900+8-900+5=900×5-(1+2+5-2-7+8+5);
(4)把4化成1+1+1+1,原式=99999+9999+999+99+9+5-1=99999+9999+999+99+9+1+1+1+1+1-1=(99999+1)+(9999+1)+(999+1)+(99+1)+(9+1)-1.
解答:解:(1)736+302
=736+300+2
=1036+2
=1038;
(2)682-298
=682-300+2
=382+2
=384;
(3)901+902+905+898-907+908-895
=900+1+900+2+900+5+900-2-900-7+900+8-900+5
=(900+900+900+900-900+900-900)+(1+2+5-2-7+8+5)
=900×3+12
=2700+12
=2712;
(4)99999+9999+999+99+9+4
=99999+9999+999+99+9+5-1
=99999+9999+999+99+9+1+1+1+1+1-1
=(99999+1)+(9999+1)+(999+1)+(99+1)+(9+1)-1
=100000+10000+1000+100+10-1
=111110-1
=111109.
=736+300+2
=1036+2
=1038;
(2)682-298
=682-300+2
=382+2
=384;
(3)901+902+905+898-907+908-895
=900+1+900+2+900+5+900-2-900-7+900+8-900+5
=(900+900+900+900-900+900-900)+(1+2+5-2-7+8+5)
=900×3+12
=2700+12
=2712;
(4)99999+9999+999+99+9+4
=99999+9999+999+99+9+5-1
=99999+9999+999+99+9+1+1+1+1+1-1
=(99999+1)+(9999+1)+(999+1)+(99+1)+(9+1)-1
=100000+10000+1000+100+10-1
=111110-1
=111109.
点评:此题考查了运算定律与简便运算,四则混合运算.注意运算顺序和运算法则,灵活运用所学的运算定律进行简便计算.
练习册系列答案
相关题目