题目内容
求未知数x.
:X=
:
X-
=
X+
X=
.
| 1 |
| 10 |
| 1 |
| 8 |
| 1 |
| 4 |
| 3 |
| 4 |
| 1 |
| 4 |
| 1 |
| 2 |
| 2 |
| 3 |
| 3 |
| 5 |
| 7 |
| 10 |
分析:(1)根据比例的基本性质,把原式转化为
x=
×
,再根据等式的性质,在方程两边同时乘上8求解
(2)根据等式的性质,在方程两边同时加上
,再乘上
求解
(3)先化简,再根据等式的性质,在方程两边同时乘上
求解
| 1 |
| 8 |
| 1 |
| 10 |
| 1 |
| 4 |
(2)根据等式的性质,在方程两边同时加上
| 1 |
| 4 |
| 4 |
| 3 |
(3)先化简,再根据等式的性质,在方程两边同时乘上
| 15 |
| 19 |
解答:解:(1)
:x=
:
,
x=
×
,
x×8=
×8,
x=
;
(2)
x-
=
,
x-
+
=
+
,
x×
=
×
,
x=1;
(3)
x+
x=
,
x=
,
x×
=
×
,
x=
.
| 1 |
| 10 |
| 1 |
| 8 |
| 1 |
| 4 |
| 1 |
| 8 |
| 1 |
| 10 |
| 1 |
| 4 |
| 1 |
| 8 |
| 1 |
| 40 |
x=
| 1 |
| 5 |
(2)
| 3 |
| 4 |
| 1 |
| 4 |
| 1 |
| 2 |
| 3 |
| 4 |
| 1 |
| 4 |
| 1 |
| 4 |
| 1 |
| 2 |
| 1 |
| 4 |
| 3 |
| 4 |
| 4 |
| 3 |
| 3 |
| 4 |
| 4 |
| 3 |
x=1;
(3)
| 2 |
| 3 |
| 3 |
| 5 |
| 7 |
| 10 |
| 19 |
| 15 |
| 7 |
| 10 |
| 19 |
| 15 |
| 15 |
| 19 |
| 7 |
| 10 |
| 15 |
| 19 |
x=
| 21 |
| 38 |
点评:本题考查了学生根据比例的基本性质和等式的性质解方程的能力,注意等号对齐.
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