题目内容
计算:(1+
+
)×(
+
+
+
)-(1+
+
+
+
)×(
+
)
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考点:分数的巧算
专题:计算问题(巧算速算)
分析:设
+
=a,
+
+
+
=b,原式变为(a+1)×b-(b+1)×a,化简后得b-a,然后代入数据计算即可.
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解答:
解:设
+
=a,
+
+
+
=b,得:
(1+
+
)×(
+
+
+
)-(1+
+
+
+
)×(
+
)
=(a+1)×b-(b+1)×a
=ab+b-ab-a
=b-a
=(
+
+
+
)-(
+
)
=
+
=
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(1+
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=(a+1)×b-(b+1)×a
=ab+b-ab-a
=b-a
=(
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=
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=
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点评:对于有相同部分的算式,一般采取用字母代替的方法,使计算简便.
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