题目内容
计算.
×[
÷(
×
)]; (
+
)÷
+
; 110×[56×(
-
)]; (
-
)÷(8×
).
| 1 |
| 8 |
| 1 |
| 2 |
| 3 |
| 5 |
| 10 |
| 9 |
| 1 |
| 5 |
| 1 |
| 4 |
| 9 |
| 7 |
| 7 |
| 10 |
| 3 |
| 7 |
| 3 |
| 8 |
| 1 |
| 2 |
| 1 |
| 3 |
| 1 |
| 4 |
考点:分数的四则混合运算
专题:运算顺序及法则
分析:(1)先算小括号里面的乘法,再算中括号里面的除法,最后算括号外面的乘法;
(2)先算括号里面的加法,再算除法,最后算括号外面的加法;
(3)括号里面利用乘法分配律简算,最后算括号外面的乘法;
(4)先算减法与乘法,最后算除法.
(2)先算括号里面的加法,再算除法,最后算括号外面的加法;
(3)括号里面利用乘法分配律简算,最后算括号外面的乘法;
(4)先算减法与乘法,最后算除法.
解答:
解:(1)
×[
÷(
×
)]
=
×[
×
]
=
×
=
;
(2)(
+
)÷
+
=
×
+
=
+
=
;
(3)110×[56×(
-
)]
=110×[56×
-56×
]
=110×[24-21]
=110×3
=330;
(4)(
-
)÷(8×
)
=
÷2
=
×
=
.
| 1 |
| 8 |
| 1 |
| 2 |
| 3 |
| 5 |
| 10 |
| 9 |
=
| 1 |
| 8 |
| 1 |
| 2 |
| 3 |
| 2 |
=
| 1 |
| 8 |
| 3 |
| 4 |
=
| 3 |
| 32 |
(2)(
| 1 |
| 5 |
| 1 |
| 4 |
| 9 |
| 7 |
| 7 |
| 10 |
=
| 9 |
| 20 |
| 7 |
| 9 |
| 7 |
| 10 |
=
| 7 |
| 20 |
| 7 |
| 10 |
=
| 21 |
| 20 |
(3)110×[56×(
| 3 |
| 7 |
| 3 |
| 8 |
=110×[56×
| 3 |
| 7 |
| 3 |
| 8 |
=110×[24-21]
=110×3
=330;
(4)(
| 1 |
| 2 |
| 1 |
| 3 |
| 1 |
| 4 |
=
| 1 |
| 6 |
=
| 1 |
| 6 |
| 1 |
| 2 |
=
| 1 |
| 12 |
点评:分数混合运算的关键是抓住运算顺序,正确按运算顺序计算,适当利用运算定律简算.
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