题目内容

2
5
÷(
2
5
+
3
4
)

(
1
2
+
1
4
-
1
6
)×12

9
15
×
14
17
+
8
17
×
14
15

[1-(
2
3
+
1
5
1
13
7
10

(1-
1
2
-
1
4
-
1
8
-
1
16
-
1
32
-
1
64
)÷
1
64
分析:算式(1)(4)根据四则混合运算的运算顺序计算即可:先算乘除,再算加减,有括号的要先算括号里面的;
算式(2)(5)根据乘法分配律计算即可;
算式(3)可根据乘法交换律及分配律计算.
解答:解:(1)
2
5
÷(
2
5
+
3
4

=
2
5
÷
23
20

=
8
23


(2)(
1
2
+
1
4
-
1
6
)×12
=
1
2
×12+
1
4
×12-
1
6
×12,
=6+3-2,
=7;

(3)
9
15
×
14
17
+
8
17
×
14
15

=
14
15
×
9
17
+
8
17
×
14
15

=(
9
17
+
8
17
)×
14
15

=1×
14
15

=
14
15


(4)[1-(
2
3
+
1
5
)×
1
13
7
10

=[1-
13
15
×
1
13
10
7

=[1-
1
15
10
7

=
14
15
×
10
7

=
4
3


(5)(1-
1
2
-
1
4
-
1
8
-
1
16
-
1
32
-
1
64
)÷
1
64

=(1-
1
2
-
1
4
-
1
8
-
1
16
-
1
32
-
1
64
)×64,
=1×64-
1
2
×64-
1
4
×64-
1
8
×64-
1
16
×64-
1
32
×64-
1
64
×64,
=64-32-16-8-4-2-1,
=1.
点评:当算式中同时含有中括号与小括号时,要先算小括号里面的,再算中括号里面的.
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