题目内容
| 2 |
| 5 |
| 2 |
| 5 |
| 3 |
| 4 |
(
| 1 |
| 2 |
| 1 |
| 4 |
| 1 |
| 6 |
| 9 |
| 15 |
| 14 |
| 17 |
| 8 |
| 17 |
| 14 |
| 15 |
[1-(
| 2 |
| 3 |
| 1 |
| 5 |
| 1 |
| 13 |
| 7 |
| 10 |
(1-
| 1 |
| 2 |
| 1 |
| 4 |
| 1 |
| 8 |
| 1 |
| 16 |
| 1 |
| 32 |
| 1 |
| 64 |
| 1 |
| 64 |
分析:算式(1)(4)根据四则混合运算的运算顺序计算即可:先算乘除,再算加减,有括号的要先算括号里面的;
算式(2)(5)根据乘法分配律计算即可;
算式(3)可根据乘法交换律及分配律计算.
算式(2)(5)根据乘法分配律计算即可;
算式(3)可根据乘法交换律及分配律计算.
解答:解:(1)
÷(
+
)
=
÷
,
=
;
(2)(
+
-
)×12
=
×12+
×12-
×12,
=6+3-2,
=7;
(3)
×
+
×
=
×
+
×
,
=(
+
)×
,
=1×
,
=
;
(4)[1-(
+
)×
]÷
=[1-
×
]×
,
=[1-
]×
,
=
×
,
=
;
(5)(1-
-
-
-
-
-
)÷
=(1-
-
-
-
-
-
)×64,
=1×64-
×64-
×64-
×64-
×64-
×64-
×64,
=64-32-16-8-4-2-1,
=1.
| 2 |
| 5 |
| 2 |
| 5 |
| 3 |
| 4 |
=
| 2 |
| 5 |
| 23 |
| 20 |
=
| 8 |
| 23 |
(2)(
| 1 |
| 2 |
| 1 |
| 4 |
| 1 |
| 6 |
=
| 1 |
| 2 |
| 1 |
| 4 |
| 1 |
| 6 |
=6+3-2,
=7;
(3)
| 9 |
| 15 |
| 14 |
| 17 |
| 8 |
| 17 |
| 14 |
| 15 |
=
| 14 |
| 15 |
| 9 |
| 17 |
| 8 |
| 17 |
| 14 |
| 15 |
=(
| 9 |
| 17 |
| 8 |
| 17 |
| 14 |
| 15 |
=1×
| 14 |
| 15 |
=
| 14 |
| 15 |
(4)[1-(
| 2 |
| 3 |
| 1 |
| 5 |
| 1 |
| 13 |
| 7 |
| 10 |
=[1-
| 13 |
| 15 |
| 1 |
| 13 |
| 10 |
| 7 |
=[1-
| 1 |
| 15 |
| 10 |
| 7 |
=
| 14 |
| 15 |
| 10 |
| 7 |
=
| 4 |
| 3 |
(5)(1-
| 1 |
| 2 |
| 1 |
| 4 |
| 1 |
| 8 |
| 1 |
| 16 |
| 1 |
| 32 |
| 1 |
| 64 |
| 1 |
| 64 |
=(1-
| 1 |
| 2 |
| 1 |
| 4 |
| 1 |
| 8 |
| 1 |
| 16 |
| 1 |
| 32 |
| 1 |
| 64 |
=1×64-
| 1 |
| 2 |
| 1 |
| 4 |
| 1 |
| 8 |
| 1 |
| 16 |
| 1 |
| 32 |
| 1 |
| 64 |
=64-32-16-8-4-2-1,
=1.
点评:当算式中同时含有中括号与小括号时,要先算小括号里面的,再算中括号里面的.
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