题目内容
|
x-
|
4÷
|
分析:(1)等式的两边同时加上
,然后等式的两边同时除以
即可;
(2)先计算x-
x=
x,然后等式的两边同时除以
即可;
(3)等式的两边同时乘
x,把原式改写成
x×
=4,再计算
x×
=
x,然后等式的两边同时除以
即可.
| 1 |
| 4 |
| 3 |
| 4 |
(2)先计算x-
| 2 |
| 3 |
| 1 |
| 3 |
| 1 |
| 3 |
(3)等式的两边同时乘
| 2 |
| 3 |
| 2 |
| 3 |
| 2 |
| 5 |
| 2 |
| 3 |
| 2 |
| 5 |
| 4 |
| 15 |
| 4 |
| 15 |
解答:解:
(1)
x-
=
,
x-
+
=
+
,
x=
,
x÷
=
÷
,
x=
;
(2)x-
x=
,
x=
,
x÷
=
÷
,
x=
;
(3)4÷
x=
,
4÷
x×
x=
×
x,
x×
=4,
x=4,
x÷
=4÷
,
x=15.
(1)
| 3 |
| 4 |
| 1 |
| 4 |
| 2 |
| 5 |
| 3 |
| 4 |
| 1 |
| 4 |
| 1 |
| 4 |
| 2 |
| 5 |
| 1 |
| 4 |
| 3 |
| 4 |
| 13 |
| 20 |
| 3 |
| 4 |
| 3 |
| 4 |
| 13 |
| 20 |
| 3 |
| 4 |
x=
| 13 |
| 15 |
(2)x-
| 2 |
| 3 |
| 2 |
| 9 |
| 1 |
| 3 |
| 2 |
| 9 |
| 1 |
| 3 |
| 1 |
| 3 |
| 2 |
| 9 |
| 1 |
| 3 |
x=
| 2 |
| 3 |
(3)4÷
| 2 |
| 3 |
| 2 |
| 5 |
4÷
| 2 |
| 3 |
| 2 |
| 3 |
| 2 |
| 5 |
| 2 |
| 3 |
| 2 |
| 3 |
| 2 |
| 5 |
| 4 |
| 15 |
| 4 |
| 15 |
| 4 |
| 15 |
| 4 |
| 15 |
x=15.
点评:本题主要考查解方程,根据等式的性质进行解答即可.
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