题目内容
解方程
|
|
X÷
|
X-
|
分析:(1)等式的两边同时加上
,然后等式的两边再同时除以
即可;
(2)先计算
X-
X=
X,然后等式的两边同时除以
即可;
(3)等式的两边同时乘
即可;
(4)先计算X-
X=
X,然后等式的两边同时除以
即可.
| 1 |
| 4 |
| 3 |
| 4 |
(2)先计算
| 2 |
| 3 |
| 3 |
| 8 |
| 7 |
| 24 |
| 7 |
| 24 |
(3)等式的两边同时乘
| 1 |
| 5 |
(4)先计算X-
| 2 |
| 3 |
| 1 |
| 3 |
| 1 |
| 3 |
解答:解:(1)
x-
=
,
x-
+
=
+
,
x=
,
x÷
=
÷
,
x=
;
(2)
X-
X=
,
X=
,
X÷
=
÷
,
X=
;
(3)X÷
=25,
X÷
×
=25×
,
X=5;
(4)X-
X=
,
X=
,
X÷
=
÷
,
X=
.
| 3 |
| 4 |
| 1 |
| 4 |
| 2 |
| 5 |
| 3 |
| 4 |
| 1 |
| 4 |
| 1 |
| 4 |
| 2 |
| 5 |
| 1 |
| 4 |
| 3 |
| 4 |
| 13 |
| 20 |
| 3 |
| 4 |
| 3 |
| 4 |
| 13 |
| 20 |
| 3 |
| 4 |
x=
| 13 |
| 15 |
(2)
| 2 |
| 3 |
| 3 |
| 8 |
| 7 |
| 16 |
| 7 |
| 24 |
| 7 |
| 16 |
| 7 |
| 24 |
| 7 |
| 24 |
| 7 |
| 16 |
| 7 |
| 24 |
X=
| 3 |
| 2 |
(3)X÷
| 1 |
| 5 |
X÷
| 1 |
| 5 |
| 1 |
| 5 |
| 1 |
| 5 |
X=5;
(4)X-
| 2 |
| 3 |
| 2 |
| 9 |
| 1 |
| 3 |
| 2 |
| 9 |
| 1 |
| 3 |
| 1 |
| 3 |
| 2 |
| 9 |
| 1 |
| 3 |
X=
| 2 |
| 3 |
点评:本题主要考查解方程,根据等式的性质进行解答即可.
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