题目内容
递等式计算(能简算的要简算)
4920÷24×20.
4
-
×1
2
+1.85+1
+7.15
1.4+(
-0.25)÷1
1.4×3
-1
×2
3.3×[38+3
÷(1
-0.15)].
解:4920÷24×20
=205×20
=4100;
-
×
=
-
×
=
-
=
;
+1.85+
+7.15
=(
+
)+(1.85+7.15)
=4+9
=13;
1.4+(
-0.25)÷
=1.4+0.375÷1.25
=1.4+0.3
=1.7;
1.4×
-
×
=1.4×(
-
)
=1.4×1
=1.4;
3.3×[38+
÷(
÷0.15)]
=3.8×[38+
÷(
×
)]
=3.8×[38+
÷
]
=3.8×[38+
×
]
=
×
=
×
=
=
.
分析:带分数乘除法要先把带分数化成假分数在计算,整数、小数、分数加减混合运算一般把分数(能化成有限小数的)化成小数计算比较简便.
点评:此题主要考查,整数、小数、分数四则混合运算的运算顺序和计算方法,及利用运算定律进行简算的能力.
=205×20
=4100;
=
=
=
=(
=4+9
=13;
1.4+(
=1.4+0.375÷1.25
=1.4+0.3
=1.7;
1.4×
=1.4×(
=1.4×1
=1.4;
3.3×[38+
=3.8×[38+
=3.8×[38+
=3.8×[38+
=
=
=
=
分析:带分数乘除法要先把带分数化成假分数在计算,整数、小数、分数加减混合运算一般把分数(能化成有限小数的)化成小数计算比较简便.
点评:此题主要考查,整数、小数、分数四则混合运算的运算顺序和计算方法,及利用运算定律进行简算的能力.
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