题目内容
1-
|
55
| ||||||||||||||||
| 9999×9999+19999 | 77×13+255×999-510. |
分析:(1)1-
×{1-
×[1-
×(1-
)]},根据分数四则混合运算的顺序,按照分数四则运算的计算法则进行计算.
(2)55
×
+145
×
,把带分数化成假分数,再根据分数的乘法法则计算.
(3)9999×9999+19999,把19999变成(10000+9999),然后运用乘法分配律进行简算.
(4)77×13+255×999-510.根据整数四则混合运算的顺序,按照整数四则运算的计算法则计算.
| 1 |
| 2 |
| 1 |
| 3 |
| 1 |
| 4 |
| 1 |
| 5 |
(2)55
| 1 |
| 17 |
| 17 |
| 18 |
| 1 |
| 11 |
| 11 |
| 12 |
(3)9999×9999+19999,把19999变成(10000+9999),然后运用乘法分配律进行简算.
(4)77×13+255×999-510.根据整数四则混合运算的顺序,按照整数四则运算的计算法则计算.
解答:解:(1)1-
×{1-
×[1-
×(1-
)]},
=1-
×{1-
×[1-
×
]},
=1-
×{1-
×[1-
]},
=1-
×{1-
×
},
=1-
×{1-
},
=1-
×
,
=1-
,
=
;
(2)55
×
+145
×
,
=
×
+
×
,
=52+133,
=185;
(3)9999×9999+19999,
=9999×9999+10000+9999,
=9999×(9999+1)+10000,
=9999×10000+10000,
=(9999+1)×10000,
=10000×10000,
=100000000;
(4)77×13+255×999-510,
=1001+254745-510,
=255236.
| 1 |
| 2 |
| 1 |
| 3 |
| 1 |
| 4 |
| 1 |
| 5 |
=1-
| 1 |
| 2 |
| 1 |
| 3 |
| 1 |
| 4 |
| 4 |
| 5 |
=1-
| 1 |
| 2 |
| 1 |
| 3 |
| 1 |
| 5 |
=1-
| 1 |
| 2 |
| 1 |
| 3 |
| 4 |
| 5 |
=1-
| 1 |
| 2 |
| 4 |
| 15 |
=1-
| 1 |
| 2 |
| 11 |
| 15 |
=1-
| 11 |
| 30 |
=
| 19 |
| 30 |
(2)55
| 1 |
| 17 |
| 17 |
| 18 |
| 1 |
| 11 |
| 11 |
| 12 |
=
| 936 |
| 17 |
| 17 |
| 18 |
| 1596 |
| 11 |
| 11 |
| 12 |
=52+133,
=185;
(3)9999×9999+19999,
=9999×9999+10000+9999,
=9999×(9999+1)+10000,
=9999×10000+10000,
=(9999+1)×10000,
=10000×10000,
=100000000;
(4)77×13+255×999-510,
=1001+254745-510,
=255236.
点评:此题考查的目的是掌握整数、分数四则混合运算的顺序及它们的计算法则,并且能够灵活选择简便方法进行计算.
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