题目内容
| 1 |
| 1×3×5 |
| 1 |
| 3×5×7 |
| 1 |
| 5×7×9 |
| 1 |
| 7×9×11 |
| 1 |
| 9×11×13 |
| 1 |
| 11×13×15 |
考点:分数的拆项
专题:计算问题(巧算速算)
分析:根据拆项公式
=
×(
+
-
),先把每一项拆项,然后根据乘法的分配律提取
,再通过加减相互抵消简算即可.
| 1 |
| (n-2)n(n+2) |
| 1 |
| 8 |
| 1 |
| n-2 |
| 1 |
| n+2 |
| 2 |
| n |
| 1 |
| 8 |
解答:
解:
+
+
+
+
+
=
×(
+
-
)+
×(
+
-
)+
×(
+
-
)+
×(
+
-
)+
×(
+
-
)+
×(
+
-
)
=
×(
+
-
+
+
-
+
+
-
+
+
-
+
+
-
+
+
-
)
=
×(1-
-
+
)
=
×(
-
)
=
×
=
故答案为:
.
| 1 |
| 1×3×5 |
| 1 |
| 3×5×7 |
| 1 |
| 5×7×9 |
| 1 |
| 7×9×11 |
| 1 |
| 9×11×13 |
| 1 |
| 11×13×15 |
=
| 1 |
| 8 |
| 1 |
| 1 |
| 1 |
| 5 |
| 2 |
| 3 |
| 1 |
| 8 |
| 1 |
| 3 |
| 1 |
| 7 |
| 2 |
| 5 |
| 1 |
| 8 |
| 1 |
| 5 |
| 1 |
| 9 |
| 2 |
| 7 |
| 1 |
| 8 |
| 1 |
| 7 |
| 1 |
| 11 |
| 2 |
| 9 |
| 1 |
| 8 |
| 1 |
| 9 |
| 1 |
| 13 |
| 2 |
| 11 |
| 1 |
| 8 |
| 1 |
| 11 |
| 1 |
| 15 |
| 2 |
| 13 |
=
| 1 |
| 8 |
| 1 |
| 1 |
| 1 |
| 5 |
| 2 |
| 3 |
| 1 |
| 3 |
| 1 |
| 7 |
| 2 |
| 5 |
| 1 |
| 5 |
| 1 |
| 9 |
| 2 |
| 7 |
| 1 |
| 7 |
| 1 |
| 11 |
| 2 |
| 9 |
| 1 |
| 9 |
| 1 |
| 13 |
| 2 |
| 11 |
| 1 |
| 11 |
| 1 |
| 15 |
| 2 |
| 13 |
=
| 1 |
| 8 |
| 1 |
| 3 |
| 1 |
| 13 |
| 1 |
| 15 |
=
| 1 |
| 8 |
| 2 |
| 3 |
| 2 |
| 195 |
=
| 1 |
| 8 |
| 128 |
| 195 |
=
| 16 |
| 195 |
故答案为:
| 16 |
| 195 |
点评:本题关键是明确分母是连续奇数的分数的拆项公式.
练习册系列答案
相关题目