题目内容
解方程:
(1-
)x=14
37.5+20%x=69.5
x-
x=
.
(1-
| 2 |
| 4 |
37.5+20%x=69.5
x-
| 7 |
| 15 |
| 14 |
| 25 |
分析:(1)把原式变为
x=14,根据等式的性质,两边同乘2即可;
(2)把20%化成小数0.2,原式变为37.5+0.2x=69.5,根据等式的性质,两边同减去37.5,再同除以0.2即可;
(3)运用乘法分配律,把原式变为(1-
)x=
,即
x=
,根据等式的性质,两边同除以
即可.
| 1 |
| 2 |
(2)把20%化成小数0.2,原式变为37.5+0.2x=69.5,根据等式的性质,两边同减去37.5,再同除以0.2即可;
(3)运用乘法分配律,把原式变为(1-
| 7 |
| 15 |
| 14 |
| 25 |
| 8 |
| 15 |
| 14 |
| 25 |
| 8 |
| 15 |
解答:解:(1)(1-
)x=14,
x=14,
x×2=14×2,
x=28;
(2)37.5+20%x=69.5,
37.5+0.2x=69.5,
37.5-37.5+0.2x=69.5-37.5,
0.2x=32,
0.2x÷0.2=32÷0.2,
x=160;
(3)x-
x=
,
(1-
)x=
,
x=
,
x÷
=
÷
,
x=
×
,
x=
.
| 2 |
| 4 |
| 1 |
| 2 |
| 1 |
| 2 |
x=28;
(2)37.5+20%x=69.5,
37.5+0.2x=69.5,
37.5-37.5+0.2x=69.5-37.5,
0.2x=32,
0.2x÷0.2=32÷0.2,
x=160;
(3)x-
| 7 |
| 15 |
| 14 |
| 25 |
(1-
| 7 |
| 15 |
| 14 |
| 25 |
| 8 |
| 15 |
| 14 |
| 25 |
| 8 |
| 15 |
| 8 |
| 15 |
| 14 |
| 25 |
| 8 |
| 15 |
x=
| 14 |
| 25 |
| 15 |
| 8 |
x=
| 21 |
| 20 |
点评:此题考查了根据等式的性质解方程,即方程两边同加、同减、同乘或同除以某数(0除外),方程的左右两边仍相等;注意“=”号上下要对齐.
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