题目内容
(1+
+
)×(
+
+
)-(1+
+
+
)×(
+
)= .
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考点:分数的巧算
专题:计算问题(巧算速算)
分析:通过观察,此题数字很接近,于是可设
+
=a,
+
+
=b,然后代入计算,求得结果.
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解答:
解:设
+
=a,
+
+
=b,则:
(1+
+
)×(
+
+
)-(1+
+
+
)×(
+
)
=(1+a)×b-(1+b)×a
=b+ab-a-ab
=b-a
=(
+
+
)-(
+
)
=
故答案为:
.
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(1+
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=(1+a)×b-(1+b)×a
=b+ab-a-ab
=b-a
=(
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=
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故答案为:
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点评:对于数字很接近的算式,一般采取用字母代替数的方法,然后代入计算.
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