题目内容
脱式计算
①6.25-40÷16×2.5
②
+(4
-3
)÷
③(8
-10.5×
)÷4
④2
÷[5
-4.5×(20%+
)].
①6.25-40÷16×2.5
②
| 1 |
| 12 |
| 5 |
| 12 |
| 1 |
| 2 |
| 11 |
| 24 |
③(8
| 5 |
| 6 |
| 4 |
| 5 |
| 1 |
| 3 |
④2
| 7 |
| 20 |
| 3 |
| 4 |
| 1 |
| 3 |
分析:算式①可根据乘法交换律计算式中的“40÷16×2.5”.
算式②③根据四则混合运算的运算顺序计算即可:先算乘除,再算加减,有括号的要先算括号里面的;
算式④可根据乘法分配律计算算式中的“4.5×(20%+
)”.
算式②③根据四则混合运算的运算顺序计算即可:先算乘除,再算加减,有括号的要先算括号里面的;
算式④可根据乘法分配律计算算式中的“4.5×(20%+
| 1 |
| 3 |
解答:解:①6.25-40÷16×2.5
=6.25-40×2.5÷16,
=6.25-100÷16,
=6.25-6.25,
=0;
②
+(4
-3
)÷
=
+(
-
)×
,
=
+
×
,
=
+2,
=2
;
③(8
-10.5×
)÷4
=(8
-8
)÷
,
=(
-
)×
,
=(
-
)×
,
=
×
,
=
;
④2
÷[5
-4.5×(20%+
)].
=2.35÷[5.75-(4.5×20%+4.5×
)],
=2.35÷[5.75-(0.9+1.5)],
=2.35÷[5.75-2.4],
=2.35÷3.35,
=
.
=6.25-40×2.5÷16,
=6.25-100÷16,
=6.25-6.25,
=0;
②
| 1 |
| 12 |
| 5 |
| 12 |
| 1 |
| 2 |
| 11 |
| 24 |
=
| 1 |
| 12 |
| 53 |
| 12 |
| 42 |
| 12 |
| 24 |
| 11 |
=
| 1 |
| 12 |
| 11 |
| 12 |
| 24 |
| 11 |
=
| 1 |
| 12 |
=2
| 1 |
| 12 |
③(8
| 5 |
| 6 |
| 4 |
| 5 |
| 1 |
| 3 |
=(8
| 5 |
| 6 |
| 2 |
| 5 |
| 13 |
| 3 |
=(
| 53 |
| 6 |
| 42 |
| 5 |
| 3 |
| 13 |
=(
| 265 |
| 30 |
| 252 |
| 30 |
| 3 |
| 13 |
=
| 13 |
| 30 |
| 3 |
| 13 |
=
| 1 |
| 10 |
④2
| 7 |
| 20 |
| 3 |
| 4 |
| 1 |
| 3 |
=2.35÷[5.75-(4.5×20%+4.5×
| 1 |
| 3 |
=2.35÷[5.75-(0.9+1.5)],
=2.35÷[5.75-2.4],
=2.35÷3.35,
=
| 47 |
| 67 |
点评:当算式中同时含有分数与小数时,要根据式中数据的特点灵活将它们互化后再进行计算.
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