题目内容
计算:(1-
)×(1+
)×(1-
)×(1+
)×…×(1-
).
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| 1998 |
分析:把每个括号里的结果计算出来,第一个括号里的差是
,第二个括号的和是
,第三个括号的差是
,…
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解答:解:(1-
)×(1+
)×(1-
)×(1+
)×…×(1-
),
=
×(
×
)×(
×
)+…+(
×
),
=
×1,
=
.
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| 1998 |
=
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| 1987 |
| 1987 |
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=
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=
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点评:此题考查学生的观察能力,以及灵活计算的能力.
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