题目内容
用递等式计算.
6÷
-
÷6
(10000-0.16×1900)÷96
×[
÷(
-
)]
1÷[(
-
)÷
]
12-5÷9-
×13.
6÷
| 3 |
| 5 |
| 3 |
| 5 |
(10000-0.16×1900)÷96
| 3 |
| 8 |
| 8 |
| 9 |
| 5 |
| 6 |
| 3 |
| 4 |
1÷[(
| 7 |
| 8 |
| 1 |
| 4 |
| 5 |
| 12 |
12-5÷9-
| 1 |
| 9 |
(1)6÷
-
÷6,
=6×
-
×
,
=10-
,
=9
;
(2)(10000-0.16×1900)÷96,
=(10000-304)÷96,
=9696÷96,
=101;
(3)
×[
÷(
-
)],
=
×[
÷
],
=
×
×12,
=4;
(4)1÷[(
-
)÷
],
=1÷[
×
],
=1÷
,
=
;
(5)12-5÷9-
×13
=12-
-
,
=12-(
+
),
=12-2,
=10.
| 3 |
| 5 |
| 3 |
| 5 |
=6×
| 5 |
| 3 |
| 3 |
| 5 |
| 1 |
| 6 |
=10-
| 1 |
| 10 |
=9
| 9 |
| 10 |
(2)(10000-0.16×1900)÷96,
=(10000-304)÷96,
=9696÷96,
=101;
(3)
| 3 |
| 8 |
| 8 |
| 9 |
| 5 |
| 6 |
| 3 |
| 4 |
=
| 3 |
| 8 |
| 8 |
| 9 |
| 1 |
| 12 |
=
| 3 |
| 8 |
| 8 |
| 9 |
=4;
(4)1÷[(
| 7 |
| 8 |
| 1 |
| 4 |
| 5 |
| 12 |
=1÷[
| 5 |
| 8 |
| 12 |
| 5 |
=1÷
| 3 |
| 2 |
=
| 2 |
| 3 |
(5)12-5÷9-
| 1 |
| 9 |
=12-
| 5 |
| 9 |
| 13 |
| 9 |
=12-(
| 5 |
| 9 |
| 13 |
| 9 |
=12-2,
=10.
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