题目内容

用递等式计算.
3
5
-
3
5
÷6
(10000-0.16×1900)÷96
3
8
×[
8
9
÷(
5
6
-
3
4
)]
1÷[(
7
8
-
1
4
)÷
5
12
]
12-5÷9-
1
9
×13.
(1)6÷
3
5
-
3
5
÷6,
=6×
5
3
-
3
5
×
1
6

=10-
1
10

=9
9
10


(2)(10000-0.16×1900)÷96,
=(10000-304)÷96,
=9696÷96,
=101;

(3)
3
8
×[
8
9
÷(
5
6
-
3
4
)],
=
3
8
×[
8
9
÷
1
12
],
=
3
8
×
8
9
×12,
=4;

(4)1÷[(
7
8
-
1
4
)÷
5
12
],
=1÷[
5
8
×
12
5
],
=1÷
3
2

=
2
3


(5)12-5÷9-
1
9
×13
=12-
5
9
-
13
9

=12-(
5
9
+
13
9
),
=12-2,
=10.
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