题目内容
求未知数x的值.
|
x-1=
|
分析:(1)根据比例的基本性质转化为
x=
×
,再根据等式的基本性质,方程的两边同除以
即可;
(2)先计算
x+
x+
x+
x+
x=
x,再根据等式的基本性质,方程的两边同
x,再加上1即可.
| 1 |
| 3 |
| 1 |
| 20 |
| 16 |
| 9 |
| 1 |
| 3 |
(2)先计算
| 1 |
| 2 |
| 1 |
| 4 |
| 1 |
| 8 |
| 1 |
| 16 |
| 1 |
| 32 |
| 15 |
| 16 |
| 15 |
| 16 |
解答:解:
:0.05=1
:x,
x=
×
,
x÷
=
×
÷
,
x=
;
(2)x-1=
x+
x+
x+
x+
x,
x-1=
x,
x-1-
x=
x-
x,
x-1=0,
x-1+1=0+1,
x=1,
x=32.
| 1 |
| 3 |
| 7 |
| 9 |
| 1 |
| 3 |
| 1 |
| 20 |
| 16 |
| 9 |
| 1 |
| 3 |
| 1 |
| 3 |
| 1 |
| 20 |
| 16 |
| 9 |
| 1 |
| 3 |
x=
| 4 |
| 15 |
(2)x-1=
| 1 |
| 2 |
| 1 |
| 4 |
| 1 |
| 8 |
| 1 |
| 16 |
| 1 |
| 32 |
x-1=
| 31 |
| 32 |
x-1-
| 31 |
| 32 |
| 31 |
| 32 |
| 31 |
| 32 |
| 1 |
| 32 |
| 1 |
| 32 |
| 1 |
| 32 |
x=32.
点评:本题主要考查学生依据等式的性质,以及比例基本性质解方程的能力,解答时注意对齐等号.
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