题目内容

用递等式计算
36÷[(
2
3
-
2
5
3
5
)]

1÷[(
7
12
-
1
6
)×3]

7
20
×(1-
5
14
÷
5
7
)
36÷[(
2
3
-
2
5
)÷
3
5
]
=36÷[
4
15
×
5
3
],
=36×
9
4

=81;

1÷[(
7
12
-
1
6
)×3]
=1÷[
5
12
×
3],
=1×
4
5

=
4
5


7
20
×(1-
5
14
÷
5
7

=
7
20
×(1-
1
2
),
=
7
20
×
1
2

=
7
40
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