题目内容
用递等式计算
36÷[(
-
)÷
)]
1÷[(
-
)×3]
×(1-
÷
).
36÷[(
| 2 |
| 3 |
| 2 |
| 5 |
| 3 |
| 5 |
1÷[(
| 7 |
| 12 |
| 1 |
| 6 |
| 7 |
| 20 |
| 5 |
| 14 |
| 5 |
| 7 |
36÷[(
-
)÷
]
=36÷[
×
],
=36×
,
=81;
1÷[(
-
)×3]
=1÷[
×3],
=1×
,
=
;
×(1-
÷
)
=
×(1-
),
=
×
,
=
.
| 2 |
| 3 |
| 2 |
| 5 |
| 3 |
| 5 |
=36÷[
| 4 |
| 15 |
| 5 |
| 3 |
=36×
| 9 |
| 4 |
=81;
1÷[(
| 7 |
| 12 |
| 1 |
| 6 |
=1÷[
| 5 |
| 12 |
=1×
| 4 |
| 5 |
=
| 4 |
| 5 |
| 7 |
| 20 |
| 5 |
| 14 |
| 5 |
| 7 |
=
| 7 |
| 20 |
| 1 |
| 2 |
=
| 7 |
| 20 |
| 1 |
| 2 |
=
| 7 |
| 40 |
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