题目内容
仔细观察,简便计算
×
+
×
-
;
×0.375×0.25÷(0.5×
×
)
| 6 |
| 13 |
| 5 |
| 25 |
| 5 |
| 13 |
| 24 |
| 25 |
| 5 |
| 13 |
| 3 |
| 10 |
| 3 |
| 5 |
| 1 |
| 8 |
分析:(1)可根据乘法积不变的规律将
×
变为
×
后,再根据乘法分配律计算.
(2)可将式中的小数化成分数后,根据一个数除以几个数的积,等于用这个数分别除以这几个数除法性质及乘法交换律、结合律计算.
| 6 |
| 13 |
| 5 |
| 25 |
| 6 |
| 13 |
| 5 |
| 25 |
(2)可将式中的小数化成分数后,根据一个数除以几个数的积,等于用这个数分别除以这几个数除法性质及乘法交换律、结合律计算.
解答:解:
(1)
×
+
×
-
=
×
+
×
-
=(
+
-1)×
=
×
=
.
=(
+
)×
+
×
-
=
×
+
×
+
×
-
=
×
+
×
+
×
-
=(
+
+
-1)×
=
×
=
;
(2)
×0.375×0.25÷(0.5×
×
)
=
×
×
÷
÷
÷
=(
×
)×(
×8)×(
×2)
=
×3×
=
.
(1)
| 6 |
| 13 |
| 5 |
| 25 |
| 5 |
| 13 |
| 24 |
| 25 |
| 5 |
| 13 |
=
| 5 |
| 13 |
| 6 |
| 25 |
| 5 |
| 13 |
| 24 |
| 25 |
| 5 |
| 13 |
=(
| 6 |
| 25 |
| 24 |
| 25 |
| 5 |
| 13 |
=
| 1 |
| 5 |
| 5 |
| 13 |
=
| 1 |
| 13 |
=(
| 5 |
| 13 |
| 1 |
| 13 |
| 5 |
| 25 |
| 5 |
| 13 |
| 24 |
| 25 |
| 5 |
| 13 |
=
| 5 |
| 13 |
| 5 |
| 25 |
| 1 |
| 13 |
| 5 |
| 25 |
| 5 |
| 13 |
| 24 |
| 25 |
| 5 |
| 13 |
=
| 5 |
| 13 |
| 5 |
| 25 |
| 5 |
| 13 |
| 1 |
| 25 |
| 5 |
| 13 |
| 24 |
| 25 |
| 5 |
| 13 |
=(
| 5 |
| 25 |
| 1 |
| 25 |
| 24 |
| 25 |
| 5 |
| 13 |
=
| 1 |
| 5 |
| 5 |
| 13 |
=
| 1 |
| 13 |
(2)
| 3 |
| 10 |
| 3 |
| 5 |
| 1 |
| 8 |
=
| 3 |
| 10 |
| 3 |
| 8 |
| 1 |
| 4 |
| 1 |
| 2 |
| 3 |
| 5 |
| 1 |
| 8 |
=(
| 3 |
| 10 |
| 5 |
| 3 |
| 3 |
| 8 |
| 1 |
| 4 |
=
| 1 |
| 2 |
| 1 |
| 2 |
=
| 3 |
| 4 |
点评:完成此类题目要注意分析式中数据的特点,然后运用合适的方法计算.
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