题目内容
| 解方程 x-
|
x÷
| ||||||||
x÷
|
| ||||||||
x÷
|
分析:(1)先化简方程,再依据等式的性质,方程两边同时除以
求解,
(2)依据等式的性质,方程两边同时乘
求解,
(3)依据等式的性质,方程两边同时减
,再同时除以
求解,
(4)依据等式的性质,方程两边同时除以
求解,
(5)依据等式的性质,方程两边同时乘
求解.
| 1 |
| 4 |
(2)依据等式的性质,方程两边同时乘
| 3 |
| 8 |
(3)依据等式的性质,方程两边同时减
| 1 |
| 5 |
| 7 |
| 5 |
(4)依据等式的性质,方程两边同时除以
| 2 |
| 3 |
(5)依据等式的性质,方程两边同时乘
| 1 |
| 4 |
解答:解:(1)x-
x=
x=
x÷
=
÷
x=1
;
(2)x÷
=
x÷
×
=
×
x=
;
(3)x÷
+
=
x÷
+
-
=
-
x÷
×
=
×
x=1
;
(4)
x=7
x÷
=7÷
x=10
;
(5)x÷
=
x÷
×
=
×
x=
.
| 3 |
| 4 |
| 3 |
| 10 |
| 1 |
| 4 |
| 3 |
| 10 |
| 1 |
| 4 |
| 1 |
| 4 |
| 3 |
| 10 |
| 1 |
| 4 |
x=1
| 1 |
| 5 |
(2)x÷
| 3 |
| 8 |
| 4 |
| 9 |
x÷
| 3 |
| 8 |
| 3 |
| 8 |
| 4 |
| 9 |
| 3 |
| 8 |
x=
| 1 |
| 6 |
(3)x÷
| 7 |
| 5 |
| 1 |
| 5 |
| 4 |
| 5 |
x÷
| 7 |
| 5 |
| 1 |
| 5 |
| 1 |
| 5 |
| 4 |
| 5 |
| 1 |
| 5 |
x÷
| 7 |
| 5 |
| 7 |
| 5 |
| 3 |
| 5 |
| 7 |
| 5 |
x=1
| 1 |
| 25 |
(4)
| 2 |
| 3 |
| 2 |
| 3 |
| 2 |
| 3 |
| 2 |
| 3 |
x=10
| 1 |
| 2 |
(5)x÷
| 1 |
| 4 |
| 9 |
| 10 |
x÷
| 1 |
| 4 |
| 1 |
| 4 |
| 9 |
| 10 |
| 1 |
| 4 |
x=
| 9 |
| 40 |
点评:本题主要考查学生依据等式的性质解方程的能力,解方程时注意对齐等号.
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