题目内容
解方程.
①
x+18=48 ②x:
=14:
.
①
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分析:①
x+18=48,此题利用等式的性质解答,等式两边先同时减去18,然后同时除以
即可求出;
②x:
=14:
,先运用比例的基本性质将原方程转化为
x=
×14,然后根据等式的性质,方程两边同除以
即可.
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②x:
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解答:解:①
x+18=48,
x+18-18=48-18,
x÷
=30÷
,
x=30×
,
x=45;
②x:
=14:
,
x=
×14,
x÷
=4÷
,
x=4×
,
x=10.
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x=30×
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x=45;
②x:
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x=4×
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x=10.
点评:在解答方程时,一般要根据等式的性质来进行求解.
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