题目内容
(2013?成都)列递等式计算.
(1)
-
+
-
=
(2)56÷
×
=
(3)(
-
)÷
×
=
(4)14×
-
÷14=
(5)1
÷[32
-(32.4-
×0.25)]×12=
(6)
=.
(1)
| 7 |
| 8 |
| 3 |
| 5 |
| 1 |
| 8 |
| 2 |
| 5 |
(2)56÷
| 7 |
| 10 |
| 5 |
| 7 |
(3)(
| 11 |
| 12 |
| 1 |
| 6 |
| 1 |
| 18 |
| 1 |
| 3 |
(4)14×
| 14 |
| 39 |
| 14 |
| 39 |
(5)1
| 1 |
| 9 |
| 2 |
| 5 |
| 1 |
| 3 |
(6)
20
| ||||||
2+1
|
分析:(1)利用加法交换律与结合律简算即可;
(2)按照从左到右的顺序计算即可;
(3)先算小括号里面的减法,再按照从左到右的顺序计算即可;
(4)把除法改为乘法,再利用乘法分配律简算即可;
(5)先算小括号里面的乘法,再算里面的减法,进一步算中括号里面的减法,最后在按从左到右运算顺序计算;
(6)分子分母相除,再按四则混合运算的顺序计算即可.
(2)按照从左到右的顺序计算即可;
(3)先算小括号里面的减法,再按照从左到右的顺序计算即可;
(4)把除法改为乘法,再利用乘法分配律简算即可;
(5)先算小括号里面的乘法,再算里面的减法,进一步算中括号里面的减法,最后在按从左到右运算顺序计算;
(6)分子分母相除,再按四则混合运算的顺序计算即可.
解答:解:(1)
-
+
-
=
+
-(
+
)
=1-1
=0;
(2)56÷
×
=56×
×
=
;
(3)(
-
)÷
×
=
×18×
=
;
(4)14×
-
÷14
=14×
-
×
=
×(14-
)
=
×
=5;
(5)1
÷[32
-(32.4-
×0.25)]×12
=1
÷[32
-(32.4-
)]×12
=1
÷[32
-32.4+
]×12
=
×12×12
=160;
(6)
=(20
-6
×
)÷(2+1
÷4
)
=(20
-
×
)÷(2+
×
)
=(20
-2
)÷(2+
)
=18×
=
.
| 7 |
| 8 |
| 3 |
| 5 |
| 1 |
| 8 |
| 2 |
| 5 |
=
| 7 |
| 8 |
| 1 |
| 8 |
| 3 |
| 5 |
| 2 |
| 5 |
=1-1
=0;
(2)56÷
| 7 |
| 10 |
| 5 |
| 7 |
=56×
| 10 |
| 7 |
| 5 |
| 7 |
=
| 400 |
| 7 |
(3)(
| 11 |
| 12 |
| 1 |
| 6 |
| 1 |
| 18 |
| 1 |
| 3 |
=
| 3 |
| 4 |
| 1 |
| 3 |
=
| 9 |
| 2 |
(4)14×
| 14 |
| 39 |
| 14 |
| 39 |
=14×
| 14 |
| 39 |
| 14 |
| 39 |
| 1 |
| 14 |
=
| 14 |
| 39 |
| 1 |
| 14 |
=
| 14 |
| 39 |
| 195 |
| 14 |
=5;
(5)1
| 1 |
| 9 |
| 2 |
| 5 |
| 1 |
| 3 |
=1
| 1 |
| 9 |
| 2 |
| 5 |
| 1 |
| 12 |
=1
| 1 |
| 9 |
| 2 |
| 5 |
| 1 |
| 12 |
=
| 10 |
| 9 |
=160;
(6)
20
| ||||||
2+1
|
=(20
| 1 |
| 2 |
| 1 |
| 4 |
| 2 |
| 5 |
| 2 |
| 3 |
| 1 |
| 6 |
=(20
| 1 |
| 2 |
| 25 |
| 4 |
| 2 |
| 5 |
| 5 |
| 3 |
| 6 |
| 25 |
=(20
| 1 |
| 2 |
| 1 |
| 2 |
| 2 |
| 5 |
=18×
| 5 |
| 12 |
=
| 15 |
| 2 |
点评:计算注意运算顺序,结合数字特点以及运算符号,灵活进行计算.
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