题目内容
计算:
(2.25÷0.375×
-0.3×2
)÷(2.3×0.25+0.27×2.5)=
.
(2.25÷0.375×
| 1 |
| 6 |
| 2 |
| 3 |
| 4 |
| 25 |
| 4 |
| 25 |
分析:本题根据四则混合运算的运算顺序计算即可.其中第二个括号内的算式可将式中的2.3×0.25根据乘法算式的性质变为0.23×2.5后,再据乘法分配律计算.
解答:解:(2.25÷0.375×
-0.3×2
)÷(2.3×0.25+0.27×2.5)
=(
×
×
-
×
)÷(0.23×2.5+0.27×2.5),
=(1-
)÷[(0.23+0.27)×2.5],
=
÷[0.5×2.5],
=
÷
,
=
.
故答案为:
.
| 1 |
| 6 |
| 2 |
| 3 |
=(
| 9 |
| 4 |
| 8 |
| 3 |
| 1 |
| 6 |
| 3 |
| 10 |
| 8 |
| 3 |
=(1-
| 4 |
| 5 |
=
| 1 |
| 5 |
=
| 1 |
| 5 |
| 5 |
| 4 |
=
| 4 |
| 25 |
故答案为:
| 4 |
| 25 |
点评:完成本题要细心,注意小数、分数之间的互化及通分约分.
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