题目内容

(1)5678-1999                             (2)8765+1998
(3)1+2+3+…+99+100                        (4)2+4+6+…+100
(5)规定a△b=3×a-2×b,①求 3△2,2△3;②求(17△6)△2.
分析:(1)把1999凑整,看作2000-1,然后再计算;
(2)把1998凑整,看作2000-2,然后再计算;
(3)(4)运用高斯求和公式计算;
(5)先仔细观察特特例,据其特点进行计算.
解答:解:(1)5678-1999,
=5678-(2000-1),
=5678-2000+1,
=3678+1,
=3679;

(2)8765+1998,
=8765+(2000-2),
=8765+2000-2,
=6765-2,
=6763;

(3)1+2+3+…+99+100,
=(1+100)×100÷2,
=101×100÷2,
=10100÷2,
=5050;

(4)2+4+6+…+100,
=(2+100)×50÷2,
=2550;

(5)a△b=3×a-2×b,
3△2,
=3×3-2×2,
=9-4,
=5;

2△3,
=3×2-2×3,
=6-6,
=0;

(17△6)△2,
=(3×17-2×6)△2,
=(51-12)△2,
=39△2,
=3×39-2×2,
=117-4,
=113.
点评:认真观察,根据数字特点,运用运算技巧,灵活解答.
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