题目内容

递等式计算
12.04-5.37-4.63 [6.85-(0.75+0.2)]÷0.5 0.125×0.25×32
9597×96 34÷[(35-14)×37].
分析:①运用减法的性质进行计算即可.
②⑤根据四则混合运算的运算顺序计算即可.
③运用乘法的结合律、交换律进行计算即可.
④运用乘法分配律计算即可.
解答:解:①12.04-5.37-4.63,
=12.04-(5.37+4.63),
=12.04-10,
=2.04;

②[6.85-(0.75+0.2)]÷0.5,
=[6.85-0.95)]÷0.5,
=5.9÷0.5,
=11.8;

③0.125×0.25×32,
=0.125×0.25×4×8,
=(0.125×8)×(0.25×4),
=1×1,
=1;

④9597×96,
=9597×(100-4),
=959700-38388,
=921312;

⑤34÷[(35-14)×37],
=34÷[21×37],
=34÷777,
=
34
777
点评:完成本题要注意分析式中数据,运用合适的简便方法计算.
练习册系列答案
相关题目

违法和不良信息举报电话:027-86699610 举报邮箱:58377363@163.com

精英家教网