题目内容
递等式计算
| 12.04-5.37-4.63 | [6.85-(0.75+0.2)]÷0.5 | 0.125×0.25×32 |
| 9597×96 | 34÷[(35-14)×37]. |
分析:①运用减法的性质进行计算即可.
②⑤根据四则混合运算的运算顺序计算即可.
③运用乘法的结合律、交换律进行计算即可.
④运用乘法分配律计算即可.
②⑤根据四则混合运算的运算顺序计算即可.
③运用乘法的结合律、交换律进行计算即可.
④运用乘法分配律计算即可.
解答:解:①12.04-5.37-4.63,
=12.04-(5.37+4.63),
=12.04-10,
=2.04;
②[6.85-(0.75+0.2)]÷0.5,
=[6.85-0.95)]÷0.5,
=5.9÷0.5,
=11.8;
③0.125×0.25×32,
=0.125×0.25×4×8,
=(0.125×8)×(0.25×4),
=1×1,
=1;
④9597×96,
=9597×(100-4),
=959700-38388,
=921312;
⑤34÷[(35-14)×37],
=34÷[21×37],
=34÷777,
=
.
=12.04-(5.37+4.63),
=12.04-10,
=2.04;
②[6.85-(0.75+0.2)]÷0.5,
=[6.85-0.95)]÷0.5,
=5.9÷0.5,
=11.8;
③0.125×0.25×32,
=0.125×0.25×4×8,
=(0.125×8)×(0.25×4),
=1×1,
=1;
④9597×96,
=9597×(100-4),
=959700-38388,
=921312;
⑤34÷[(35-14)×37],
=34÷[21×37],
=34÷777,
=
| 34 |
| 777 |
点评:完成本题要注意分析式中数据,运用合适的简便方法计算.
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