题目内容
| 递等式计算 1÷(
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分析:(1)(4)先算括号内的,再算括号外的;
(2)先算乘法,再算减法;
(3)把除法改为乘法,运用乘法交换律与结合律简算;
(5)把除法改为乘法,约分计算;
(6)先算除法,再算加法.
(2)先算乘法,再算减法;
(3)把除法改为乘法,运用乘法交换律与结合律简算;
(5)把除法改为乘法,约分计算;
(6)先算除法,再算加法.
解答:解:(1)1÷(
÷
),
=1÷(
×3),
=1÷
,
=
;
(2)
-
×
,
=
-
,
=
;
(3)
×8÷
×8,
=
×8×
×8,
=(
×
)×(8×8),
=
×64,
=
;
(4)
×(
-
),
=
×
,
=
;
(5)
÷
×
,
=
×
×
,
=
;
(6)
+
÷
,
=
+
×
,
=
+
,
=
.
| 1 |
| 2 |
| 1 |
| 3 |
=1÷(
| 1 |
| 2 |
=1÷
| 3 |
| 2 |
=
| 2 |
| 3 |
(2)
| 3 |
| 8 |
| 3 |
| 10 |
| 5 |
| 6 |
=
| 3 |
| 8 |
| 1 |
| 4 |
=
| 1 |
| 8 |
(3)
| 3 |
| 13 |
| 10 |
| 13 |
=
| 3 |
| 13 |
| 13 |
| 10 |
=(
| 3 |
| 13 |
| 13 |
| 10 |
=
| 3 |
| 10 |
=
| 96 |
| 5 |
(4)
| 3 |
| 10 |
| 5 |
| 7 |
| 10 |
| 21 |
=
| 3 |
| 10 |
| 5 |
| 21 |
=
| 1 |
| 14 |
(5)
| 9 |
| 10 |
| 7 |
| 22 |
| 14 |
| 33 |
=
| 9 |
| 10 |
| 22 |
| 7 |
| 14 |
| 33 |
=
| 6 |
| 5 |
(6)
| 3 |
| 8 |
| 5 |
| 8 |
| 15 |
| 16 |
=
| 3 |
| 8 |
| 5 |
| 8 |
| 16 |
| 15 |
=
| 3 |
| 8 |
| 2 |
| 3 |
=
| 25 |
| 24 |
点评:考查了分数的四则混合运算,注意运算顺序和运算法则,灵活运用所学的运算定律简便计算.
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