题目内容
2.5×[
÷4
×(0.92-0.88)]×6.3.
| 17 |
| 28 |
| 1 |
| 4 |
分析:本题根据四则混合运算的运算法则计算即可:先算乘除,再算加减,有括号的要先算括号里面的.计算过程中可利用乘法交换律及结合律计算.
解答:解:2.5×[
÷4
×(0.92-0.88)]×6.3
=2.5×[
÷
×0.04]×6.3,
=2.5×[
×
×0.04]×6.3,
=2.5×
×0.4×6.3,
=(2.5×0.4)×(
×6.3),
=1×0.9,
=0.9.
| 17 |
| 28 |
| 1 |
| 4 |
=2.5×[
| 17 |
| 28 |
| 17 |
| 4 |
=2.5×[
| 17 |
| 28 |
| 4 |
| 17 |
=2.5×
| 1 |
| 7 |
=(2.5×0.4)×(
| 1 |
| 7 |
=1×0.9,
=0.9.
点评:要搞清四则混合运算的运算顺序:当算式中同时含有中括号与小括号时,要先算小括号里面的,再算中括号里面的,最后算括号外面的.
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