题目内容
计算.
|
24×(
|
(
|
13÷39+(
|
分析:(1)(3)根据四则混合运算的运算顺序计算即可:先算乘除,再算加减,有括号的要先算括号里面的;
(2)可根据乘法分配律进行计算;
(4)可根据乘法分配律及加法交换律进行计算.
(2)可根据乘法分配律进行计算;
(4)可根据乘法分配律及加法交换律进行计算.
解答:解:(1)
×(
-
)
=
×(
-
),
=
×
,
=
;
(2)24×(
+
+
)
=24×
+24×
+24×
,
=9+6+
,
=15
;
(3)(
-
)÷(
-
)
=(
-
)÷(
-
),
=
÷
,
=
;
(4)13÷39+(
+
)×13
=13×
+
×13+
×13,
=
+
+
,
=
+
+
;
=1
.
| 3 |
| 4 |
| 9 |
| 10 |
| 5 |
| 6 |
=
| 3 |
| 4 |
| 27 |
| 30 |
| 25 |
| 30 |
=
| 3 |
| 4 |
| 2 |
| 30 |
=
| 1 |
| 20 |
(2)24×(
| 3 |
| 8 |
| 1 |
| 4 |
| 1 |
| 48 |
=24×
| 3 |
| 8 |
| 1 |
| 4 |
| 1 |
| 48 |
=9+6+
| 1 |
| 2 |
=15
| 1 |
| 2 |
(3)(
| 5 |
| 8 |
| 1 |
| 2 |
| 8 |
| 9 |
| 1 |
| 3 |
=(
| 5 |
| 8 |
| 4 |
| 8 |
| 8 |
| 9 |
| 3 |
| 9 |
=
| 1 |
| 8 |
| 5 |
| 9 |
=
| 9 |
| 40 |
(4)13÷39+(
| 1 |
| 26 |
| 2 |
| 39 |
=13×
| 1 |
| 39 |
| 1 |
| 26 |
| 2 |
| 39 |
=
| 1 |
| 3 |
| 1 |
| 2 |
| 2 |
| 3 |
=
| 1 |
| 3 |
| 2 |
| 3 |
| 1 |
| 2 |
=1
| 1 |
| 2 |
点评:完成有关于分数四则混合运算题目时要细心,注意通分约分.
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