题目内容
1+
+
+
+
+…+
.
| 5 |
| 3 |
| 11 |
| 6 |
| 19 |
| 10 |
| 29 |
| 15 |
| 9899 |
| 4950 |
分析:通过观察,每个分数都比2小一个分数单位,于是原式变为1+2-
+2-
+2-
+2-
+…+2-
,整数与整数、分数与分数分别相加,提出2后,每个分数又可以拆分为两个分数相减的形式,然后通过分数加减相互抵消,求得结果.
| 1 |
| 3 |
| 1 |
| 6 |
| 1 |
| 10 |
| 1 |
| 15 |
| 1 |
| 4950 |
解答:解:1+
+
+
+
+…+
,
=1+2-
+2-
+2-
+2-
+…+2-
,
=1+2×99-(
+
+
+
+…+
),
=1+198-2×(
+
+
+
+…+
),
=199-2×(
-
+
-
+
-
+
-
+…+
-
),
=199-2×(
-
),
=199-(1-
),
=199-
,
=198
.
| 5 |
| 3 |
| 11 |
| 6 |
| 19 |
| 10 |
| 29 |
| 15 |
| 9899 |
| 4950 |
=1+2-
| 1 |
| 3 |
| 1 |
| 6 |
| 1 |
| 10 |
| 1 |
| 15 |
| 1 |
| 4950 |
=1+2×99-(
| 1 |
| 3 |
| 1 |
| 6 |
| 1 |
| 10 |
| 1 |
| 15 |
| 1 |
| 4950 |
=1+198-2×(
| 1 |
| 6 |
| 1 |
| 12 |
| 1 |
| 20 |
| 1 |
| 30 |
| 1 |
| 9900 |
=199-2×(
| 1 |
| 2 |
| 1 |
| 3 |
| 1 |
| 3 |
| 1 |
| 4 |
| 1 |
| 4 |
| 1 |
| 5 |
| 1 |
| 5 |
| 1 |
| 6 |
| 1 |
| 99 |
| 1 |
| 100 |
=199-2×(
| 1 |
| 2 |
| 1 |
| 100 |
=199-(1-
| 1 |
| 50 |
=199-
| 49 |
| 50 |
=198
| 1 |
| 50 |
点评:解决这类题目,应仔细审题,根据数字特点,运用拆分法进行解题.
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