题目内容
(2013?成都模拟)计算:100+121+144+169+…+400=
2585
2585
.分析:100=102,121=112,144=122,…根据公式12+22+32+…+n2=
计算.
| n(n+1)(2n+1) |
| 6 |
解答:解:100+121+144+169+…+400,
=102+112+122+…+202,
=(12+22+32+42+…202)-(12+22+32+42+52+62+72+82+92),
=
-
,
=
-
,
=2870-285,
=2585.
故答案为:2585.
=102+112+122+…+202,
=(12+22+32+42+…202)-(12+22+32+42+52+62+72+82+92),
=
| 20×(20+1)×(2×20+1) |
| 6 |
| 9×(9+1)×(2×9+1) |
| 6 |
=
| 20×21×41 |
| 6 |
| 9×10×19 |
| 6 |
=2870-285,
=2585.
故答案为:2585.
点评:本题关键是仔细观察,找出计算的方法,运用公式解答.
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