题目内容

5÷[(35%-
1
12
)×
3
4
]+
1
3

1
8
×2.75+0.125×
17
4
+12.5%
(362+548×361)÷(362×548-186)
1
1
×
1
4
+
1
4
×
1
7
+
1
7
×
1
10
+…+
1
97
×
1
100
分析:(1)按运算顺序计算,先算小括号里的,再算中括号里的,最后算括号外的;
(2)根据数字特点,把分数化为小数,然后用乘法分配律的逆运算简算;
(3)此题如果直接计算,会较麻烦,所以要寻找简便的算法.前后两个括号内的数字有一定特点,通过变形,前后两个括号内的算式相同,故答案为1;
(4)此题设计较新颖,如果直接计算会很麻烦,这就要寻求简便的算法,可先把原式变为:
1
3
×(1-
1
4
)+
1
3
×(
1
4
-
1
7
)+
1
3
×(
1
7
-
1
10
)+…+
1
3
×(
1
97
-
1
100
),这样就很明朗了.
解答:解:(1)5÷[(35%-
1
12
)×
3
4
]+
1
3

=5÷[(
7
20
-
1
12
)×
3
4
]+
1
3

=5÷[(
21
60
-
5
60
)×
3
4
]+
1
3

=5÷[
16
60
×
3
4
]+
1
3

=5÷
1
5
+
1
3

=25+
1
3

=25
1
3


(2)
1
8
×2.75+0.125×
17
4
+12.5%,
=0.125×2.75+0.125×4.25+0.125,
=(2.75+4.25+1)×0.125,
=8×0.125,
=1;

(3)(362+548×361)÷(362×548-186),
=[362+548×(362-1)]÷(362×548-186),
=[362-548+548×362]÷(362×548-186),
=(362×548-186)÷(362×548-186),
=1;

(4)
1
1
×
1
4
+
1
4
×
1
7
+
1
7
×
1
10
+…+
1
97
×
1
100

=
1
3
×(1-
1
4
)+
1
3
×(
1
4
-
1
7
)+
1
3
×(
1
7
-
1
10
)+…+
1
3
×(
1
97
-
1
100
),
=
1
3
×(1-
1
4
+
1
4
-
1
7
+
1
7
-
1
10
+…+
1
97
-
1
100
),
=
1
3
×(1-
1
100
),
=
33
100
点评:此题考查了运算顺序,以及运用所学知识灵活巧算的能力.
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