题目内容
脱式计算.
| ①1.3×2.5÷0.65 | ②2.65-0.87-3.13+4.35 | ||||||||||||||
③
|
④
|
分析:①1.3×2.5÷0.65根据四则运算的顺序计算;
②2.65-0.87-3.13+4.35利用加法的交换律和一个数连续减去两个数等于这个数减去这两个数的和变成(2.65+4.35)-(0.87+3.13)计算简便;
③把
×
变成
×
再利用乘法的分配律计算简便;
④按四则运算的顺序,先算小括号里的,再算中括号里的,最后算括号外面的.
②2.65-0.87-3.13+4.35利用加法的交换律和一个数连续减去两个数等于这个数减去这两个数的和变成(2.65+4.35)-(0.87+3.13)计算简便;
③把
| 8 |
| 13 |
| 4 |
| 9 |
| 4 |
| 13 |
| 8 |
| 9 |
④按四则运算的顺序,先算小括号里的,再算中括号里的,最后算括号外面的.
解答:解:①1.3×2.5÷0.65,
=3.25÷0.65,
=5;
②2.65-0.87-3.13+4.35,
=(2.65+4.35)-(0.87+3.13),
=7-4,
=3;
③
×
+
×
,
=
×
+
×
,
=
×(
+
),
=
;
④
÷[
-(1-
)],
=
÷[
-
],
=
÷
,
=1.
=3.25÷0.65,
=5;
②2.65-0.87-3.13+4.35,
=(2.65+4.35)-(0.87+3.13),
=7-4,
=3;
③
| 4 |
| 13 |
| 5 |
| 9 |
| 8 |
| 13 |
| 4 |
| 9 |
=
| 4 |
| 13 |
| 5 |
| 9 |
| 4 |
| 13 |
| 8 |
| 9 |
=
| 4 |
| 13 |
| 5 |
| 9 |
| 8 |
| 9 |
=
| 4 |
| 13 |
④
| 1 |
| 6 |
| 1 |
| 2 |
| 2 |
| 3 |
=
| 1 |
| 6 |
| 1 |
| 2 |
| 1 |
| 3 |
=
| 1 |
| 6 |
| 1 |
| 6 |
=1.
点评:完成本题要注意分析式中数据,运用合适的简便方法计算.
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