题目内容

脱式计算:
(1)(3.8-1.8÷2)×0.5
(2)
1
2
+
9
20
÷
9
10
-
5
8

(3)
9
10
÷[
1
2
×(
6
5
×
3
10
)].
(1)(3.8-1.8÷2)×0.5,
=(3.8-0.9)×0.5,
=2.9×0.5,
=1.45;
(2)
1
2
+
9
20
÷
9
10
-
5
8

=
1
2
+
9
20
×
10
9
-
5
8

=
1
2
+
1
2
-
5
8

=1-
5
8

=
3
8

(3)
9
10
÷[
1
2
×(
6
5
×
3
10
)],
=
9
10
÷[
1
2
×
9
25
],
=
9
10
÷
9
50

=
9
10
×
50
9

=5.
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