题目内容
计算
1.5×[0.02÷(2.1-2.09)]
÷[
-(
-
)].
1.5×[0.02÷(2.1-2.09)]
| 9 |
| 36 |
| 3 |
| 4 |
| 7 |
| 16 |
| 1 |
| 4 |
(1)1.5×[0.02÷(2.1-2.09)],
=1.5×[0.02÷0.01],
=1.5×2,
=3;
(2)
÷[
-(
-
)],
=
÷[
-
+
],
=
÷[1-
],
=
÷
,
=
.
=1.5×[0.02÷0.01],
=1.5×2,
=3;
(2)
| 9 |
| 36 |
| 3 |
| 4 |
| 7 |
| 16 |
| 1 |
| 4 |
=
| 9 |
| 36 |
| 3 |
| 4 |
| 7 |
| 16 |
| 1 |
| 4 |
=
| 9 |
| 36 |
| 7 |
| 16 |
=
| 9 |
| 36 |
| 9 |
| 16 |
=
| 4 |
| 9 |
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