题目内容
能简便的用简便方法计算.
|
15×(
|
36×(
|
16×
|
分析:(1)运用乘法交换律解答,
(2)(3)运用乘法分配律解答,
(4)运用乘法交换律和结合律解答.
(2)(3)运用乘法分配律解答,
(4)运用乘法交换律和结合律解答.
解答:解:(1)
×
×
=
×
×
=
×
=
;
(2)15×(
+
)
=15×
+15×
=3+10
=13;
(3)36×(
-
)
=36×
-36×
=21-20
=1;
(4)16×
×(9×
)
=(16×
)×(
×9)
=8×6
=48.
| 5 |
| 12 |
| 3 |
| 8 |
| 4 |
| 15 |
=
| 5 |
| 12 |
| 4 |
| 15 |
| 3 |
| 8 |
=
| 1 |
| 9 |
| 3 |
| 8 |
=
| 1 |
| 24 |
(2)15×(
| 1 |
| 5 |
| 2 |
| 3 |
=15×
| 1 |
| 5 |
| 2 |
| 3 |
=3+10
=13;
(3)36×(
| 7 |
| 12 |
| 5 |
| 9 |
=36×
| 7 |
| 12 |
| 5 |
| 9 |
=21-20
=1;
(4)16×
| 2 |
| 3 |
| 1 |
| 2 |
=(16×
| 1 |
| 2 |
| 2 |
| 3 |
=8×6
=48.
点评:本题主要考查学生运用简便方法解决问题的能力.
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