题目内容
能用简便方法计算的用简便方法计算.
25×1.25×32
(3.75+4.1+2.15)×9.8
5400-2940÷28×27
(20.2×0.4+7.88)÷4.2
(
)÷
+
10÷[
-(
÷
+
)].
解:(1)25×1.25×32,
=(25×4)×(1.25×8),
=100×10,
=1000;
(2)(3.75+4.1+2.15)×9.8,
=10×9.8,
=98;
(3)5400-2940÷28×27,
=5400-105×27,
=5400-2835,
=2565;
(4)(20.2×0.4+7.88)÷4.2,
=(8.08+7.88)÷4.2,
=15.96÷4.2,
=3.8;
(5)(
)÷
+
,
=
×
,
=
,
=
,
=
;
(6)10÷[
-(
÷
+
)],
=10÷[
-(
)],
=10÷[
-(2+
)],
=10÷[
],
=10÷[
],
=10÷
,
=10×
,
=
,
=37
.
分析:只有第一题,25×1.25×32,把32分解为4×8,再根据乘法交换律、结合律进行简算;
其它5道题根据四则混合运算的运算顺序,和小数、分数四则运算的计算法则脱式计算;
点评:此题主要考查小数、分数四则混合运算的计算,要注意分析式中数据,运用合适的简便方法计算.
=(25×4)×(1.25×8),
=100×10,
=1000;
(2)(3.75+4.1+2.15)×9.8,
=10×9.8,
=98;
(3)5400-2940÷28×27,
=5400-105×27,
=5400-2835,
=2565;
(4)(20.2×0.4+7.88)÷4.2,
=(8.08+7.88)÷4.2,
=15.96÷4.2,
=3.8;
(5)(
=
=
=
=
(6)10÷[
=10÷[
=10÷[
=10÷[
=10÷[
=10÷
=10×
=
=37
分析:只有第一题,25×1.25×32,把32分解为4×8,再根据乘法交换律、结合律进行简算;
其它5道题根据四则混合运算的运算顺序,和小数、分数四则运算的计算法则脱式计算;
点评:此题主要考查小数、分数四则混合运算的计算,要注意分析式中数据,运用合适的简便方法计算.
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