题目内容
能简算的要简算,并写出简算过程.
(1)[5.3-(4.98-5
)-1
]÷25%
(2)1999÷1999
(3)48%÷[3-(5.55×1
-2.1÷
)]
(4)3
×1234+7777÷
+543.2×38.
(1)[5.3-(4.98-5
| 7 |
| 10 |
| 1 |
| 50 |
(2)1999÷1999
| 1999 |
| 2000 |
(3)48%÷[3-(5.55×1
| 2 |
| 5 |
| 2 |
| 5 |
(4)3
| 4 |
| 5 |
| 35 |
| 186 |
分析:(1)把分数和百分数化为小数,计算比较简便先算小括号内的,再算中括号内的,最后算括号外的除法;
(2)通过观察,此题若按常规来做太复杂,这里在把除法化为假分数时,分子不必算出来,其分子部分1999×2000+1999=1999×2001,其中1999可与被除数中的1999约分;
(3)把48%化为小数,先算小括号内的乘法和除法,再算小括号内的减法,然后算中括号内的,最后算括号外的除法;
(4)先把原式变为3.8×1234+7777×
+5432×3.8,运用乘法分配律简算.
(2)通过观察,此题若按常规来做太复杂,这里在把除法化为假分数时,分子不必算出来,其分子部分1999×2000+1999=1999×2001,其中1999可与被除数中的1999约分;
(3)把48%化为小数,先算小括号内的乘法和除法,再算小括号内的减法,然后算中括号内的,最后算括号外的除法;
(4)先把原式变为3.8×1234+7777×
| 186 |
| 35 |
解答:解:(1)[5.3-(4.98-5
)-1
]÷25%,
=[5.3-(4.98-5.7)-1.02]÷0.25,
=[5.3-4.98+5.7-1.02]÷0.25,
=[5.3+5.7-(4.98+1.02)]÷0.25,
=[11-6]÷0.25,
=5÷0.25,
=20;
(2)1999÷1999
,
=1999÷
,
=1999×
,
=1999×
,
=
;
(3)48%÷[3-(5.55×1
-2.1÷
)],
=0.48÷[3-(5.55×
-2.1×2.5)],
=0.48÷[3-(7.77-5.25)],
=0.48÷[3-2.52],
=0.48÷0.48,
=1;
(4)3
×1234+7777÷
+543.2×38,
=3.8×1234+7777×
+5432×3.8,
=(1234+5432)×3.8+1111×
,
=6666×3.8+1111×37.2,
=1111×6×3.8+1111×37.2,
=1111×(22.8+37.2),
=1111×60,
=66660.
| 7 |
| 10 |
| 1 |
| 50 |
=[5.3-(4.98-5.7)-1.02]÷0.25,
=[5.3-4.98+5.7-1.02]÷0.25,
=[5.3+5.7-(4.98+1.02)]÷0.25,
=[11-6]÷0.25,
=5÷0.25,
=20;
(2)1999÷1999
| 1999 |
| 2000 |
=1999÷
| 1999×2000+1999 |
| 2000 |
=1999×
| 2000 |
| 1999×2000+1999 |
=1999×
| 2000 |
| 1999×(2000+1) |
=
| 2000 |
| 2001 |
(3)48%÷[3-(5.55×1
| 2 |
| 5 |
| 2 |
| 5 |
=0.48÷[3-(5.55×
| 7 |
| 5 |
=0.48÷[3-(7.77-5.25)],
=0.48÷[3-2.52],
=0.48÷0.48,
=1;
(4)3
| 4 |
| 5 |
| 35 |
| 186 |
=3.8×1234+7777×
| 186 |
| 35 |
=(1234+5432)×3.8+1111×
| 186 |
| 5 |
=6666×3.8+1111×37.2,
=1111×6×3.8+1111×37.2,
=1111×(22.8+37.2),
=1111×60,
=66660.
点评:脱式计算,注意运算顺序和运算法则,灵活运用运算定律和运算技巧,灵活简算.
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