题目内容
解方程
①
|
②
|
③x÷
|
分析:(1)先依据等式的性质,方程两边同时除以
,求解即可;
(2)先计算可得出
x=
,再依据等式的性质,方程两边同时除以
求解即可;
(3)先先计算可得出x÷
=
依据等式的性质,方程两边同时乘以
求解即可.
| 4 |
| 15 |
(2)先计算可得出
| 35 |
| 36 |
| 5 |
| 9 |
| 35 |
| 36 |
(3)先先计算可得出x÷
| 4 |
| 9 |
| 9 |
| 8 |
| 4 |
| 9 |
解答:解:(1)
x=1.6,
x÷
=1.6÷
,
x=6;
(2)
x÷
=
,
x=
,
x÷
=
÷
,
x=
;
(3)x÷
=
÷
,
x÷
=
,
x÷
×
=
×
,
x=
.
| 4 |
| 15 |
| 4 |
| 15 |
| 4 |
| 15 |
| 4 |
| 15 |
x=6;
(2)
| 5 |
| 6 |
| 6 |
| 7 |
| 5 |
| 9 |
| 35 |
| 36 |
| 5 |
| 9 |
| 35 |
| 36 |
| 35 |
| 36 |
| 5 |
| 9 |
| 35 |
| 36 |
x=
| 4 |
| 7 |
(3)x÷
| 4 |
| 9 |
| 15 |
| 16 |
| 5 |
| 6 |
x÷
| 4 |
| 9 |
| 9 |
| 8 |
x÷
| 4 |
| 9 |
| 4 |
| 9 |
| 9 |
| 8 |
| 4 |
| 9 |
x=
| 1 |
| 2 |
点评:本题考查了运用等式的基本性质来解方程的能力.
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