题目内容
计算:(要求写出计算过程)
(1)(
-0.1÷2)×
+1÷1
(2)84
×1.375+105
×0.9
(3)(2.5×
)÷(
÷0.8)-0.75÷
(4)8-(7.14×
-2
÷2.5)+0.
.
(1)(
| 1 |
| 4 |
| 5 |
| 13 |
| 1 |
| 12 |
(2)84
| 9 |
| 11 |
| 5 |
| 19 |
(3)(2.5×
| 4 |
| 5 |
| 1 |
| 4 |
| 3 |
| 40 |
(4)8-(7.14×
| 1 |
| 3 |
| 2 |
| 9 |
| ? |
| 1 |
分析:本题根据四则混合运算的运算顺序计算即可:先算乘除,再算加减,有括号的要先算括号里面的.
(4)的计算过程中,可根据一个数减两个数的差,等于减去这两个数中的被减数,加上减数的减法性质计算.
(4)的计算过程中,可根据一个数减两个数的差,等于减去这两个数中的被减数,加上减数的减法性质计算.
解答:解:(1)(
-0.1÷2)×
+1÷1
=(0.25-0.05)×
+1÷
,
=
×
+
,
=
+
,
=1;
(2)84
×1.375+105
×0.9
=
×
+
×
,
=116
+94
,
=(116+94)+(
+
),
=210+1
,
=211
;
(3)(2.5×
)÷(
÷0.8)-0.75÷
=(2.5×0.8)÷(
×
)-
×
,
=2×
-10,
=6
-10,
=-3
;
(4)8-(7.14×
-2
÷2.5)+0.
.
=8-(2.38-
÷
)+0.
,
=8-(2.38-
)+
,
=8-2.38+(
+
),
=5.62+1,
=6.62.
| 1 |
| 4 |
| 5 |
| 13 |
| 1 |
| 12 |
=(0.25-0.05)×
| 5 |
| 13 |
| 13 |
| 12 |
=
| 1 |
| 5 |
| 5 |
| 13 |
| 12 |
| 13 |
=
| 1 |
| 13 |
| 12 |
| 13 |
=1;
(2)84
| 9 |
| 11 |
| 5 |
| 19 |
=
| 933 |
| 11 |
| 11 |
| 8 |
| 2000 |
| 19 |
| 9 |
| 10 |
=116
| 5 |
| 8 |
| 13 |
| 19 |
=(116+94)+(
| 5 |
| 8 |
| 13 |
| 19 |
=210+1
| 47 |
| 152 |
=211
| 47 |
| 152 |
(3)(2.5×
| 4 |
| 5 |
| 1 |
| 4 |
| 3 |
| 40 |
=(2.5×0.8)÷(
| 1 |
| 4 |
| 5 |
| 4 |
| 3 |
| 4 |
| 40 |
| 3 |
=2×
| 16 |
| 5 |
=6
| 2 |
| 5 |
=-3
| 3 |
| 5 |
(4)8-(7.14×
| 1 |
| 3 |
| 2 |
| 9 |
| ? |
| 1 |
=8-(2.38-
| 20 |
| 9 |
| 5 |
| 2 |
| ? |
| 1 |
=8-(2.38-
| 8 |
| 9 |
| 1 |
| 9 |
=8-2.38+(
| 8 |
| 9 |
| 1 |
| 9 |
=5.62+1,
=6.62.
点评:算式(3)中6
-10不够减,可先用10减6
,然后在得数前加上“-”即可.
| 2 |
| 5 |
| 2 |
| 5 |
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